Answer:
<h3>0.99 m</h3>
Explanation:
Average velocity is the change of rate of displacement with respect to time;
Average velocity = Displacement/Time
Given
Average velocity of the frog = 1.8m/s
Time = 0.55s
Required
Displacement of the frog
Substitute the given parameters into the formula;
1.8 = displacement/0.55
cross multiply
Displacement = 1.8*0.55
Displacement = 0.99 m
Hence the frog's displacement is 0.99m
Answer: X
Explanation:
This situation can be illustrated as a car in circular motion (image attached).
In circular motion the acceleration vector
is always directed toward the center of the circumference (that's why it's called centripetal acceleration).
So, in this case the arrow labeled X is the only that points toward the center, hence it represents the car's centripetal acceleration
Answer:
8.67807 N
34.7123 N
Explanation:
m = Mass of shark = 92 kg
= Density of seawater = 1030 kg/m³
= Density of freshwater = 1000 kg/m³
= Density of shark = 1040 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Net force on the fin is (seawater)

The lift force required in seawater is 8.67807 N
Net force on the fin is (freshwater)

The lift force required in a river is 34.7123 N
Answer:
Explanation:
Potential due to a charged metallic sphere having charge Q and radius r on its surface will be
v = k Q / r . On the surface and inside the metallic sphere , potential is the same . Outside the sphere , at a distance R from the centre potential is
v = k Q / R
a ) On the surface of the shell , potential due to positive charge is
V₁ = 
On the surface of the shell , potential due to negative charge is
V₁ = 
Total potential will be zero . they will cancel each other.
b ) On the surface of the sphere potential
= 
= 22.5 x 10⁵ V
On the surface of the sphere potential due to outer shell
= 
= -9 x 10⁵
Total potential
=( 22.5 - 9 ) x 10⁵
= 13.5 x 10⁵ V
c ) In the space between the two , potential will depend upon the distance of the point from the common centre .
d ) Inside the sphere , potential will be same as that on the surface that is
13.5 x 10⁵ V.
e ) Outside the shell , potential due to both positive and negative charge will cancel each other so it will be zero.