Answer:The answer must be The weight of the man and the vertical distance moved.
Explanation: you calculate it by the force you applied times the distance you moved
1) 15 / 12 = 1.25 ratio
2) to increase acceleration 1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg
choose A
Answer:
Force applied to smaller cross section is
= 82.63 N
Explanation:
As we know

where
signifies the weight of the two chair in a hydraulic-lift system
And
signifies the area of the two respective chairs in a hydraulic-lift system
Given -
N
Square centimeter
Square centimeter
Substituting the given values in above equation, we get -

Force applied to smaller cross section is
= 82.63 N