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lora16 [44]
2 years ago
13

Astronomers have discovered several volcanoes on io, a moon of jupiter. one of them, named loki, ejects lava to a maximum height

of 2.00 â 105 m. suppose another volcano on a different moon ejected lava at a height of 1.89 â 105 m where the acceleration of gravity is 1.72 m/s2.
Physics
1 answer:
r-ruslan [8.4K]2 years ago
7 0
The question seems to be incomplete. However, I can think of a possible logical question this problem could have. The equation for the maximum height attained by any object thrown upwards is:

H = v²/2g

I think the question would be determining the gravity in Io assuming that the initial velocity of the lava is the same. Then, the solution is as follows:

Let's use the other volcano to find v.
1.89×10⁵ m = v²/2(1.72 m/s²)
Solving for v,
v = 806.325 m/s

So, we use this to find g in Io.
2×10⁵ m = (806.325)²/2(g)
Solving for g,
<em>g = 1.6254 m/s²</em>
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Suppose you are measuring the height of a small child. What will determine the number if significant digits you record?
slega [8]

The number of significant digits of any measurement is determined by the instrument used for such measurement. For example, in this case, we have the height of a small child being measured. We can use a simple ruler for this, and we see that a ruler has ten divisions for 1 cm. This means that the ruler cannot measure beyond the size of 0.1 cm or 1 mm. Hence, when we report the height of the small child, we report it to one significant digit after the decimal place. As an example, if we measure a child's height to be 90 full cm divisions and 8 smaller divisions, we report it as 90.8 cm but not 90.83 or 90.86 cm.

8 0
2 years ago
Case 1: A DJ starts up her phonograph player. The turntable accelerates uniformly from rest, and takes t₁ = 11.9 seconds to get
olga_2 [115]

Answer:

Part a)

\omega = 8.17 rad/s

Part b)

N = 7.74 rev

Part c)

\alpha = 0.69 rad/s^2

Part d)

\alpha = 0.48 rad/s^2

Part e)

t = 9.14 s

Explanation:

Part a)

Angular speed is given as

\omega = 2\pi f

\omega = 2\pi(\frac{78}{60})

\omega = 8.17 rad/s

Part b)

Since turn table is accelerating uniformly

so we will have

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{8.17 + 0}{2}(11.9)

2N\pi = 48.6

N = 7.74 rev

Part c)

angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{t}

\alpha = \frac{8.17 - 0}{11.9}

\alpha = 0.69 rad/s^2

Part d)

When its angular speed changes to 120 rpm

then we will have

\omega_2 = 2\pi (\frac{120}{60})

\omega_2 = 12.56 rad/s

number of turns revolved is 15 times

so we have

\omega_f^2 - \omega_i^2 = 2 \alpha \theta

12.56^2 - 8.17^2 = 2\alpha (2\pi\times 15)

\alpha = 0.48 rad/s^2

Part e)

now for uniform acceleration we have

\omega_f - \omega_i = \alpha t

12.56 - 8.17 = 0.48 t

t = 9.14 s

7 0
2 years ago
7) A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were
Elenna [48]

Answer:

A, B, and E

Explanation:

The springs are identical, and are compressed the same amount, so they have the same initial elastic potential energy. (E is true)

Energy is conserved, so the darts have the same amount of kinetic energy. (A is true, C is false)

The lighter dart has the same energy as the heavier dart.  Since it has less mass, it must have a greater speed. (B is true, D is false)

6 0
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Answer:

1.75 m/s

Explanation:

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8 0
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forsale [732]

Answer:

The Position of the object L = 0.172 m

Explanation:

The detailed explanation of the question is given in the attach document.

3 0
2 years ago
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