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Anna11 [10]
2 years ago
9

A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest

awhile and finally runs quickly back to her initial position along a straight line.
Required:
Draw displacement versus time plots best represents the student’s trip?
Physics
1 answer:
True [87]2 years ago
6 0

Answer:

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

Explanation:

In this problem we have a uniform movement, this means that the acceleration in each intervals

              x = v t

 

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

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The air in a pipe resonates at 150 Hz and 750 Hz, one of these resonances being the fundamental. If the pipe is open at both end
Xelga [282]

Answer:

Explanation:

Two frequencies with magnitude 150 Hz and 750 Hz are given

For Pipe open at both sides

fundamental frequency is 150 Hz as it is smaller

frequency  of pipe is given by

f=\frac{nv}{2L}

where L=length of Pipe

v=velocity of sound

f=150\ Hz for n=1

and f=750 is for n=5

thus there are three resonance frequencies for n=2,3 and 4

For Pipe closed at one end

frequency is given by

f=\frac{(2n+1)}{4L}\cdot v

for n=0

f_1=\frac{v}{4L}

f_1=150\ Hz

for n=2

f_2=\frac{5v}{4L}

Thus there is one additional resonance corresponding to n=1 , between f_1 and f_2

8 0
2 years ago
A diver explores a shallow reef off the coast of Belize. She initially swims d1 = 74.8 m north, makes a turn to the east and con
Nataly [62]

Answer:R=1607556m

θ=180degrees

Explanation:

d1=74.8m

d2=160.7km=160.7km*1000

d2=160700m

d3=80m

d4=198.1m

Using analytical method :

Rx=-(160700+75*cos(41.8))= -160755.9m

Ry= -(74.8+75sin(41.8))-198.1=73m

Magnitude, R:

R=√Rx+Ry

R=√160755.9^2+20^2=160755.916

R=160756m

Direction,θ:

θ=arctan(Rx/Ry)

θ=arctan(-73/160755.9)

θ=-7.9256*10^-6

Note that θ is in the second quadrant, so add 180

θ=180-7.9256*10^6=180degrees

8 0
2 years ago
Using the mass and radius of the Sun given under the "Vital Statistics" section of Chapter 10 in your textbook, calculate the Su
atroni [7]

Answer:

The density of the sun is 4434kg/m³

This was found by dividing the mass (1.989 ×10³⁰kg) by the volume (4.486×10²⁶ m³) which was calculated using V = 4/3×pi ×r³

Explanation:

See attachment below.

5 0
2 years ago
If a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s What is the angle Theta abo
cluponka [151]

Answer: C

Explanation: It's a lot of math.

7 0
2 years ago
Tara is giving a speech on the how to get a U.S. passport for the first time. During her speech, she tells the audience the requ
Alchen [17]

Answer:

a. 1. she informed the audience when she was concluding

2. She simply outlined the steps tying her conclusion to the topic

3. her conclusion was concise and simple.

b. 13.1 grams

Explanation:

a. signalling the end of a speech prepares the mind of the audience and leaves them satisfied, and Kara correctly signaled the end of her speech when she said "In conclusion".

Also, Kara summarized the ideas in her speech by simply outlining the requirements needed to get a U.S passport.

Her conclusion was concise and simple which is very important especially for lengthy speeches because the audience at this point must be getting tired and distracted.

b. Amount of cholesterol in 100 mL of blood = 248 mg

Total Volume of blood = 5.3 Liters.

the question is asking us to find the total grams of cholesterol in the individual's body, that is the total grams of cholesterol in 5.3 Liters of the individuals blood.

To solve, let us use the following steps:

1. unify the units of measuring volume.

since the first volume is given in Milliliters, I will convert the second volume (5.3 Liters) to milliliters too. To do this, note that:

1 liter = 1000 Milliliter (mL)

∴ 5.3 Liters = 5.3 × 1000 = 5300 Milliliters (mL)

2. Calculate the amount of cholesterol in 5300 mL.

100 mL = 248 mg of cholesterol

∴ 1 mL = \frac{248}{100\\} = 2.48 mg

∴ 5300 mL = 2.48 × 5300 = 13,144 mg of cholesterol.

3. Convert the amount of cholesterol from Milligram to gram

Since the question asked for the gram of cholesterol, not the milligram of cholesterol, converting from milligram to gram, we use the following steps:

1000 mg = 1 g

∴ 1 mg = \frac{1}{1000} g

∴ 13144 mg = 13144 × \frac{1}{1000} = \frac{13144}{1000} = 13.144 ≅ 13.1 g of cholesterol ( 1 decimal place).

I suggest you go and study the conversion relationships between the sub units milli, micro, centi and deci.

7 0
2 years ago
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