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Sindrei [870]
2 years ago
13

Imagine you are in a small boat on a small pond that has no inflow or outflow. If you take an anchor that was sitting on the flo

or of the boat and lower it over the side until it sits on the ground at the bottom of the pond, will the water level rise slightly, stay the same, or lower slightly?Two students, Ian and Owen, are discussing this. Ian says that the anchor will still displace just as much water when it is sitting on the bottom of the pond as it does when it is in the boat. After all, adding the anchor to the boat causes the water level in the lake to rise, and so would immersing the anchor in the pond. So Ian reasons that both displacements would be equal, and the lake level remains unchanged.
Physics
1 answer:
inn [45]2 years ago
3 0

Answer;

The pond's water level will fall.

Explanation;

Archimedes principle explains that a floating body will displace the amount of water that weighs the same as it, whereas a body resting on the bottom of the water displaces the amount of water that is equal to the body's volume.

When the anchor is in the boat it is in the category of floating body and when it is on the bottom of the pond it is in the second category.

Since anchors are naturally heavy and denser than water, the amount of water displaced when the anchor is in the boat is greater than the amount of water displaced when the anchor is on the bottom of the pond since the way anchors are doesn't make for them to have considerable volume.

When the anchor is dropped to the bottom of the pond, the water level will therefore fall. If the anchor doesn't reach the bottom it is still in the floating object category and there will be no difference to the water level, but once it touches the bottom of the pond, the water level of the pond drops.

Hope this Helps!!!

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Answer:

x = -1.437 cm

Explanation:

The general equation for position of Simple harmonic motion is given as:

x = A sin(\omega t)          ........(1)

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ω = Angular velocity

t = time

In this case, the amplitude is just half the range,

thus,

A =\frac{3cm}{2}=1.5cm  (Given range = 3cm)

A = 1.5 cm  

Now, The angular velocity is given as:

\omega=\frac{2\pi}{T}

Where, T = time period of the wave =0.27s (given)

\omega=\frac{2\pi}{0.27s}

or

\omega=23.27s^{-1}

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on solving the above equation we get,

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here the negative sign depicts the position in the opposite direction of +x

5 0
2 years ago
Which of the following statements characterizing types of waves are true?
Tasya [4]

Answer:

a and b.

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2. Longitudinal wave :

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1 .These are transverse wave or Longitudinal wave or combination of them .

2.These waves required medium for propagation.

3. The particle are vibrate perpendicular to motion of waves.

So the option a and b are correct.

7 0
2 years ago
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