answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alchen [17]
2 years ago
10

You are a particle physicist at the Large Hadron Collider who is tasked with designing an apparatus to separate annihilation pro

ducts (such as pions) from proton-antiproton collisions. Because positive and negative charges deflect differently in a magnetic field, you plan to use a magnetic field to separate these products. As a starting point, in which you ignore interaction effects and assume a known velocity, you decide to explore a beam of coincident positively and negatively charged pions, each of mass in and charge +lel and -del, respectively. These pions travel between two square sheets of a known number N of densely-packed parallel current-carrying wires, each of length L and individual current 1. Determine whether the currents in the different sheets should be in the same or opposite direction to create a magnetic field between the sheets. Then, determine whether the pion beam should be parallel or perpendicular to the wires as it travels between the sheets. Ignoring fringing effects, how strong must the wire current be so that the pions are separated by a distance of one-hundredth of the sheet length as they exit the plates?

Physics
1 answer:
JulijaS [17]2 years ago
4 0

Find solution in the attachments

You might be interested in
If you were to triple the size of the Earth (R = 3R⊕) and double the mass of the Earth (M = 2M⊕), how much would it change the g
EastWind [94]

Answer:

Decreased by a factor of 4.5

Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 are the masses of the object and Earth itself. and R distance between, or the Earth radius.

So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}

\frac{F_G}{f_g} = \frac{\frac{M_2}{R^2}}{\frac{m_2}{r^2}}

\frac{F_G}{f_g} = \frac{M_2}{R^2}\frac{r^2}{m_2}

\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2

Since M_2 = 2m_2 and r = R/3

\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5

So gravity would have been decreased by a factor of 4.5  

8 0
2 years ago
Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i
SCORPION-xisa [38]

Answer:

The value is  r =  5.077 \  m

Explanation:

From the question we are told that

   The  Coulomb constant is  k =  9.0 *10^{9} \  N\cdot  m^2  /C^2

   The  charge on the electron/proton  is  e =  1.6*10^{-19} \  C

    The  mass of proton m_{proton} =  1.67*10^{-27} \  kg

    The  mass of  electron is  m_{electron } =  9.11 *10^{-31} \ kg

Generally for the electron to be held up by the force gravity

   Then    

       Electric force on the electron  =  The  gravitational Force

i.e  

            m_{electron} *  g  = \frac{ k *  e^2  }{r^2 }

         \frac{9*10^9 *  (1.60 *10^{-19})^2  }{r^2 }  =     9.11 *10^{-31 }  *  9.81

         r =  \sqrt{25.78}

         r =  5.077  \  m

7 0
2 years ago
Sort the processes based on the type of energy transfer they involve.??
klemol [59]
The 1st one goes two added sodoes the second one then the third goes to removed then the fourth goes to added and the rest go to removed
3 0
2 years ago
Read 2 more answers
Why does increasing the number trials increase confidence in the results of the experiment?
IceJOKER [234]
If you increase the number of trials in an experiment it will make the test more valid and legitimate.As you take the same test/experiment once or twice you could see if your results are similar to each other.

6 0
2 years ago
Read 2 more answers
A uniform metal bar is 5.00 m long and has mass 0.300 kg. The bar is pivoted on a narrow support that is 2.00 m from the left-ha
Firlakuza [10]

Explanation and answer:

This type of question can be clarified and sometimes solved by drawing a proper diagram or sketch.  (see below)

Solution:

Since we do not know the reaction of the support, we can take moments about the support (thereby eliminating its involvement).

CCW moment = 0.900(5.00/2 - x) kg-m

CW moment = 0.300*(5.00/2-2.00)) = 0.150 kg-m

At equilibrium, CCW moment = CW moment, so

0.900(2.50-x) = 0.150

Expand and solve

2.25 - 0.900x = 0.150

0.900x = 2.25-0.15 = 2.10

x = 2.10 / 0.900 = 2.33 m  (to nearest cm)

8 0
2 years ago
Other questions:
  • HURRY UP PLZZZ Two identical waves are traveling toward each other in the same medium. One has a positive amplitude, meaning tha
    14·2 answers
  • When Earth’s Northern Hemisphere is tilted toward the Sun during June, some would argue that the cause of our seasons is that th
    5·1 answer
  • The force sensor measures the force on the sensor due to the bumper, but the cart's momentum change arises from the force on the
    12·1 answer
  • A friend throws a heavy ball toward you while you are standing on smooth ice. You can either catch the ball or deflect it back t
    5·1 answer
  • Technician A says test lights are great for quick tests on non-computerized circuits. Technician B says you can use a test light
    5·1 answer
  • You are standing in a boat. Which of the following strategies will make the boat start moving? Check all that apply.
    13·2 answers
  • A horizontal pipe of diameter 0.81 m has a smooth constriction to a section of diameter 0.486 m . The density of oil flowing in
    12·1 answer
  • . A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate is
    6·2 answers
  • Compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 10
    8·1 answer
  • 1 Which requires more work, lifting a 10kg sack of<br> coal or lifting a 15kg bag of feathers?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!