Answer:
D. 214 kPa
Explanation:
The absolute pressure is given by:
where
p is the absolute pressure
is the atmospheric pressure
is the gauge pressure
In this problem, we have
So, the atmospheric pressure is
You are a particle physicist at the Large Hadron Collider who is tasked with designing an apparatus to separate annihilation pro
ducts (such as pions) from proton-antiproton collisions. Because positive and negative charges deflect differently in a magnetic field, you plan to use a magnetic field to separate these products. As a starting point, in which you ignore interaction effects and assume a known velocity, you decide to explore a beam of coincident positively and negatively charged pions, each of mass in and charge +lel and -del, respectively. These pions travel between two square sheets of a known number N of densely-packed parallel current-carrying wires, each of length L and individual current 1. Determine whether the currents in the different sheets should be in the same or opposite direction to create a magnetic field between the sheets. Then, determine whether the pion beam should be parallel or perpendicular to the wires as it travels between the sheets. Ignoring fringing effects, how strong must the wire current be so that the pions are separated by a distance of one-hundredth of the sheet length as they exit the plates?
1 answer:
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Answer:
L' = 1.231L
Explanation:
The transmission coefficient, in a tunneling process in which an electron is involved, can be approximated to the following expression:
L: width of the barrier
C: constant that includes particle energy and barrier height
You have that the transmission coefficient for a specific value of L is T = 0.050. Furthermore, you have that for a new value of the width of the barrier, let's say, L', the value of the transmission coefficient is T'=0.025.
To find the new value of the L' you can write down both situation for T and T', as in the following:
Next, by properties of logarithms, you can apply Ln to both equations (1) and (2):
Next, you divide the equation (3) into (4), and finally, you solve for L':
hence, when the trnasmission coeeficient has changes to a values of 0.025, the new width of the barrier L' is 1.231 L