(A)energy lost in the lever due to friction
(C)
visual estimation of height of the beanbag
(E)position of the fulcrum for the lever affecting transfer of energy
Answer:

Explanation:
-The only relevant force is the electrostatic force
-The formula for the electrostatic force is:

E is the electric field and q is the magnitude of the charge.
#Since the electric field is the same in both cases, and the charge of the protons and electrons have the same magnitude, you can state that the magnitude of the electric forces acting in both proton and electron are the same.

-Applying Newton's 2nd Law:



#equate the two forces:

#The equations for velocity in uniform acceleration:

#For the proton:

#For the electron:

The mass values of the proton and electron are:

The speed of the ion is therefore calculated as:

Hence, the ion's speed at the negative plate is 
Answer:
5308.34 N/C
Explanation:
Given:
Surface density of each plate (σ) = 47.0 nC/m² = 
Separation between the plates (d) = 2.20 cm
We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

Now, plug in
for 'σ' and
for
and solve for the electric field. This gives,

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C
Answer:
42 degrees, virtual image, same size as the object (26 cm)
Explanation:
The law of reflection states that:
- When a ray of light is incident on a flat surface (such as the plane mirror), the angle of reflection is equal to the angle of incidence
So, since in this case the angle of incidence is 42 degrees, the angle of reflection is also 42 degrees.
Moreover, the image formed by a plane mirror is always:
- Virtual (on the same side as the object)
- The same size as the object
So in this case, since the object's size is 26 cm, the image's size is also 26 cm.
An activity that is relatively short in time <10 seconds and has few repetitions predominantly uses the ATP/PC energy system. The cellular respiration procedure that changes food energy into ATP which is a form of energy is largely reliant on oxygen obtainability. During exercise the source and request of oxygen obtainable to muscle is unnatural by period and strength and by the individual’s cardiorespiratory suitability level.
Steps of the ATP-PC system:
1. Primarily, ATP kept in the myosin cross-bridges which is microscopic contractile parts of muscle is broken down to issue energy for muscle shrinkage. This action consents the by-products of ATP breakdown which are the adenosine diphosphate and one single phosphate all on its own.
2. Phosphocreatine is then broken down by the enzyme creatine kinase into creatine and phosphate.
3. The energy free in the breakdown of PC permits ADP and Pi to rejoin creating more ATP. This newly made ATP can now be broken down to issue energy to fuel activity.