<span>v =Integral(F/m)dtv=Integral(F/m)dt
=â«50(6t2â’4t+3)/5dt=â«05(6t2â’4t+3)/5dt
=1/5â—(2t3â’2t2+3t)|(0,5)=1/5â—(2t3â’2t2+3t)|(0,5)
=1/5â—(250â’50+15)=1/5â—(250â’50+15)
=215/5=215/5
=43m/s.</span>
Answer:

Explanation:
When the screw is turned by two turns then change in the length of the wire is given as




now we know by the formula of Young's modulus

so we have



Explanation:
Below is an attachment containing the solution
<span>1.0 m/s
Momentum = mass x velocity
Total Momentum before any collision = total momentum afterwards
4.0 x 3.0= 12 :g x momentum before (x g because using weight)
Afterwards, if the velocity of the two joined is v then we get:
'momentum x g'=12v
so 12v=12
so v=1m/s</span>