A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body
1 answer:
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Summary:
m=1kg
a=8 m/s^2
g= 9,8 m/s^2
F(ar)=?
I hope to help you
m=1kg
a=8 m/s^2
g= 9,8 m/s^2
F(ar)=?
I hope to help you
Answer:
a)
b)
Explanation:
Given that
v(t) = 5 t i + t² j - 2 t³ k
We know that acceleration a is given as
Therefore the acceleration function a will be
The acceleration at t = 2 s
a= 5 i + 2 x 2 j - 6 x 2² k m/s²
a=5 i + 4 j -24 k m/s²
The magnitude of the acceleration will be
a= 24.83 m/s²
The direction of the acceleration a is given as
a)
b)
Answer:
26 days
Explanation:
m = 9.4×1021 kg
r= 1.5×108 m
F = 1.1×10^ 19 N
We know Fc =
==> 1.1 × = (9.4 ×
×
) ÷ 1.5 ×
==> 1.1 × =
× 6.26×
==> = 1.1 ×
÷ 6.26×
==> = 0.17571885 ×
==> v= 0.419188323 × m/sec
==> v= 419.188322834 m/s
Putting value of r and v from above in ;
T= 2πr ÷ v
==> T= 2×3.14×1.5× ÷ 0.419188323 ×
==> T = 22.472× 100000 = 2247200 sec
but
86400 sec = 1 day
==> 2247200 sec= 2247200 ÷ 86400 = 26 days