All categories

2 years ago

Let’s now multiply two numbers in scientific notation using Google.

Physics

2 answers:

Tatiana [17]2 years ago

6 0

Answer

Option 4, 2.33E-11

Step by step solution

Step 1

The first step is to convert the 2 numbers to decimal form as shown below,

4.48E-8= 0.0000000448

5.2E-4=0.00052

Step 2

The next step is to multiply these two numbers by entering them into then in to the google calculator as shown below,

0.0000000448*0.00052=2.329E-11

Step 3

In this step we sound the number up to 2 decimal places. This number to 2 decimal places is 2.33E-11.

olga_2 [115]2 years ago

5 0

We are going to rewrite each number:
(4.48E-8) = 0.0000000448
(5.2E-4) = 0.00052
We observe that when multiplying, the exponent will be on the order of 10 ^ -11
Doing the multiplication we have:
(4.48E-8) * (5.2E-4) = 2.3296E-11
Rewriting:
(4.48E-8) * (5.2E-4) = 2.33E-11
Answer:
2.33E-11

You might be interested in

Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i

SCORPION-xisa [38]

Answer:

The value is $r = 5.077 \ m$

Explanation:

From the question we are told that

The Coulomb constant is $k = 9.0 *10^{9} \ N\cdot m^2 /C^2$

The charge on the electron/proton is $e = 1.6*10^{-19} \ C$

The mass of proton $m_{proton} = 1.67*10^{-27} \ kg$

The mass of electron is $m_{electron } = 9.11 *10^{-31} \ kg$

Generally for the electron to be held up by the force gravity

Then

Electric force on the electron = The gravitational Force

i.e

$m_{electron} * g = \frac{ k * e^2 }{r^2 }$

$\frac{9*10^9 * (1.60 *10^{-19})^2 }{r^2 } = 9.11 *10^{-31 } * 9.81$

$r = \sqrt{25.78}$

$r = 5.077 \ m$

7 0

1 year ago

Complete the statements using data from Table A of your Student Guide. The speed of the cart after 8 seconds of Low fan speed is

finlep [7]

Answer:

The speed of the cart after 8 seconds of Low fan speed is 72.0 cm/s

The speed of the cart after 3 seconds of Medium fan speed is 36.0 cm/s

The speed of the cart after 6 seconds of High fan speed is 96.0 cm/s

Explanation:

took the test on edgenuity

4 0

1 year ago

Read 2 more answers

Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh

guajiro [1.7K]

Answer:

Total charge flow through the cooker is 21600 C

Explanation:

As we know that the current flow through the cooker is given by Ohm's law

here it is given as

$V = i R$

$i = \frac{V}{R}$

$i = \frac{120}{160}$

$i = \frac{3}{4} A$

now the charge flow through it is given as

$Q = i t$

total time is t = 8 hours

$Q = \frac{3}{4}(8 \times 60 \times 60)$

$Q = 21600 C$

7 0

2 years ago

Based on the emf value measured at frame 700, what is the average magnitude of the magnetic field inside the magnet assembly? No

Nadusha1986 [10]

Answer:

The average magnitude of magnetic field B= 0.0433/ d Tesla

(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)

Explanation:

Induced emf

where B= magnetic field

d= breadth of rectangular piece

V= velocity with which the rectangular piece = o.o6m/s

n= no of turns = 10

EMF = 26mV

since d (breadth of the frame) is not given, I will use it as a variable

EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)

From eq 1, we get

B= (EMF)/(n d V)

B= (26 X 0.001) / (10 d 0.06)

B= 0.0433/ d Tesla

4 0

1 year ago

A shot putter releases the shot some distance above the level ground with a velocity of 12.0 m/s, 51.0 ∘above the horizontal. Th

alina1380 [7]

A) Zero

The motion of the shot is a projectile's motion: this means that there is only one force acting on the projectile, which is gravity. However, gravity only acts in the vertical direction: so, there are no forces acting in the horizontal direction. Therefore, the x-component of the acceleration is zero.

B) -9.8 m/s^2

The vertical acceleration is given by the only force acting in the vertical direction, which is gravity:

$F=mg$

where m is the projectile's mass and g is the gravitational acceleration. Therefore, the y-component of the shot's acceleration is equal to the acceleration due to gravity:

$a_y = g = -9.8 m/s^2$

where the negative sign means it points downward.

C) 7.6 m/s

The x-component of the shot's velocity is given by:

$v_x = v_0 cos \theta$

where

$v_0 = 12.0 m/s$ is the initial velocity

$\theta=51.0^{\circ}$ is the angle of the shot

Substituting into the equation, we find

$v_x = (12.0 m/s)(cos 51^{\circ})=7.6 m/s$

D) 9.3 m/s

The y-component of the shot's velocity is given by:

$v_y = v_0 sin \theta$

where

$v_0 = 12.0 m/s$ is the initial velocity

$\theta=51.0^{\circ}$ is the angle of the shot

Substituting into the equation, we find

$v_y = (12.0 m/s)(sin 51^{\circ})=9.3 m/s$

E) 7.6 m/s

We said at point A) that the acceleration along the x-direction is zero: therefore, the velocity along the x-direction does not change, so the x-component of the velocity at the end of the trajectory is equal to the x-velocity at the beginning:

$v_x = 7.6 m/s$