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Vadim26 [7]
2 years ago
11

A gas of helium atoms at 273 k is in a cubical container with 25.0 cm on a side. (a) what is the minimum uncertainty in momentum

components of helium atoms? (b) what is the minimum uncertainty in velocity components? (c) find the ratio of the uncertainties in (b) to the mean speed of an atom in each direction.
Physics
1 answer:
qwelly [4]2 years ago
6 0

wave function of a particle with mass m is given by ψ(x)={ Acosαx −

π

2α

≤x≤+

π

2α

0 otherwise , where α=1.00×1010/m.

(a) Find the normalization constant.

(b) Find the probability that the particle can be found on the interval 0≤x≤0.5×10−10m.

(c) Find the particle’s average position.

(d) Find its average momentum.

(e) Find its average kinetic energy −0.5×10−10m≤x≤+0.5×10−10m.

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the millersburg ferry (m=13000.0 kg loaded) puts its engines in full reverse and stops in 65 seconds. if the speed before brakin
kenny6666 [7]

The braking force is -400 N

Explanation:

We can solve this problem by using the impulse theorem, which states that the impulse applied on the ferry (the product of force and time) is equal to its change in momentum:

F \Delta t = m(v-u)

where in this problem, we have:

F is the force applied by the brakes

\Delta t = 65 s is the time interval

m = 13,000 kg is the mass of the ferry

u = 2.0 m/s is the initial velocity

v = 0 is the final velocity

And solving for F, we find the force applied by the brakes:

F=\frac{m(v-u)}{\Delta t}=\frac{(13000)(0-2.0)}{65}=-400 N

where the negative sign indicates that the direction is backward.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

4 0
2 years ago
A car is traveling in a race.The car went from initial velocity of 35m/s to the final velocity of 65m/s in 5 seconds what was th
I am Lyosha [343]
Acceleration is the change in velocity divided by time. The change in velocity is -30m/s and time is 5s. If you divide -30m/s by 5s, you get -6m/s<span>².</span>
8 0
2 years ago
Read 2 more answers
How many significant figures are in 0.0069
posledela
Two significant figures, the 6 and the 9
7 0
2 years ago
A lens of focal length 15.0 cm is held 10.0 cm from a page (the object ). Find the magnification .
nevsk [136]

Answer:

Magnification, m = 3

Explanation:

It is given that,

Focal length of the lens, f = 15 cm

Object distance, u = -10 cm

Lens formula :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

v is image distance

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm

Magnification,

m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3

So, the magnification of the lens is 3.

3 0
2 years ago
Consider the static equilibrium diagram here. What is the angle F1 must make with the horizontal?
Nataly [62]

ANSWER


\theta=35\degree


EXPLANATION


Since the body is in equilibrium, total upward forces must equal total downward force.


Also the net horizontal forces acting on the body must be zero.



We need to resolve F_1 into vertical and horizontal components.



The horizontal component is


x=F_1\cos\theta.


The vertical component is


y=F_1\sin\theta.



Equating the up force to the downward forces gives,


F_1\sin\theta + 20N=60N.


This implies that,



F_1\sin\theta =60N-20N.




F_1\sin\theta=40N...eqn1




Also the horizontal forces must be equal.


F_1\cos\theta=57N...eqn2.



Dividing equation (1) by equation (2) gives,


\frac{F_1\sin\theta}{F_1\cos\theta}=\frac{40}{57}.


\Rightarrow \tan\theta=0.70175





\Rightarrow \theta=tan^{-1}(0.70175)


\Rightarrow \theta=35.0594.




Therefore the given angle that F_1 must make with the horizontal is approximately 35° to the nearest degree.

4 0
2 years ago
Read 2 more answers
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