A gas of helium atoms at 273 k is in a cubical container with 25.0 cm on a side. (a) what is the minimum uncertainty in momentum
1 answer:
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Answer:
The moun lives 2.198*10^-6 s as measured by its own frame of reference
The Earth moved 648 m as measured by the moun's frame of reference
Explanation:
From the point of view of the observer on Earth the muon traveled 3.53 km at 0.983c
0.983 * 3*10^8 = 2.949*10^8 m/s
Δt = d/v = 3530 / 2.949*10^8 = 1.197*10^-5 s
The muon lived 1.197*10^-5 s from the point of view of the observer.
The equation for time dilation is:
Then:
From the point of view of the moun Earth moved at 0.983c (2.949*10^8 m/s) during a time of 2.198*10^-6, so it moved
d = v*t = 2.949*10^8 * 2.198*10^-6 = 648 m
Answer:
Explanation:
Using second law of motion
where m1 is mass of block, m2 is mass of flywheel, g is acceleration due to gravity whose value is taken as
, T is torque and r is radius
Substituting 5.5 Kg for m1, 13 Kg for m2, 0.33 m for r, 2.5 Nm for T we obtain