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alexgriva [62]
1 year ago
10

Suggest one reason why the bricklayer needs a higher energy diet than the computer operator

Physics
1 answer:
sashaice [31]1 year ago
7 0

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

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A solid conducting sphere is placed in an external uniform electric field. With regard to the electric field on the sphere's int
Fittoniya [83]

Answer:

The answer is A. There is no electric field on the interior of the conducting sphere.

Explanation:

A solid conducting sphere in a uniform electric field will exert force on the charges in the sphere to redistribute themselves in such a way that both the charges and the field inside the sphere would vanish.

3 0
2 years ago
A resistor with resistance R and an air-gap capacitor of capacitance C are connected in series to a battery (whose strength is "
blsea [12.9K]

Answer:

a) Q = C*emf

b)  Reduction in electric field strength and electric potential

c) Initial current through the resistor = emf/R

d) The final charge = K*C*emf

Explanation:

a) The resistors and capacitors are connected in series with the battery

Using Kirchoff's voltage law, sum of all voltages in the circuit is zero

Let V_{R} = Voltage dropped across the Resistor

V_{c} = Voltage dropped across the capacitor

Applying KVL;

emf - V_{R}  - V_{c} = 0\\.........................(1)

Since the connection is in series, the same current flow through the circuit

V_{R} = IR\\Q = CV_{c} \\V_{c} = Q/C

Putting V_{c} and V_{R} into equation (1)

emf - IR - Q/C = 0

At the final charge, the capacitor in fully charged, and current drops to zero due to equilibrium

I = 0A\\emf = Q/C\\Q = C* emf

b) Current starts running through the plate because as the sheet of plastic is inserted between the plates both the electric field intensity and the electric potential reduces. The charge also reduces, then current flows

c) The current through the resistor is the current through the entire circuit ( series connection)

I = I_{o} \exp(\frac{-t}{RC} )\\At time the initial time, t\\t = 0\\ I_{o} = \frac{emf}{R} \\

Putting the values of t and I₀ into the formula for I written above

I = \frac{emf}{R} \exp(0)\\I = \frac{emf}{R}

d) NB: The initial charge on the capacitor = C * emf

The final charge will be:

Q = K* Q_{initial} \\Q_{initial}  = C *emf\\Q_{final}  = KCemf

4 0
2 years ago
A cyclotron particle accelerator (sometimes called an “atom smasher” in the popular press) is a device for accelerating charged
Iteru [2.4K]

Answer:

v=1.54\times 10^{7}}\ \textup{m/s}

Explanation:

Given:

The accelerated energy, U = 1.25 MeV = 1.25 × 10⁶ eV

we know,

1 eV = 1.6 × 10⁻¹⁹ J

thus,

1.25 eV = (1.6 × 10⁻¹⁹) × (1.25) J = 2 × 10⁻¹³ J

Now, Applying the law of conservation of energy, the energy due to acceleration will be equal to the kinetic energy

mathematically,

K.E = U

\frac{1}{2}mv^2=2\times 10^{-13} \ \textup{J}

where,

m = mass of the particle = 1.67 × 10⁻²⁷ kg

v = velocity of the particle

on substituting the values we get

\frac{1}{2}\times 1.67\times 10^{-27}\times v^2=2\times 10^{-13} \ \textup{J}

or

v^2=\frac{2\times 10^{-13}}{1.67\times 10^{-27}}

or

v=\sqrt{2.39\times 10^{14}}

or

v=1.54\times 10^{7}}\ \textup{m/s}

7 0
2 years ago
A child sets off the firecracker at a distance of 100 m from the family house. what is the sound intensity β100 at the house?
KATRIN_1 [288]

To solve this problem, we use the formula:

I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]

I100 / I1 = 1 / 100^2

I100 / I1 = 10^-4

 

Therefore the change in intensity from 1m to 100m in decibels is:

B100 – B1 = 10 log(10^-4) dB = -40 dB

 

So the intensity at 100m is calculated as:

B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB

 

Answer:

100 dB

6 0
1 year ago
Read 2 more answers
A sharpening wheel is traveling at 5 rad/s, it slows down to rest in 30 seconds while sharpening an axe. What is its angular acc
Ratling [72]

Answer:

Angular acceleration = 0.167 rad/s^2

Explanation:

Given

Initial Angular velocity (w1) = 5 rad/s

Final Angular velocity (w2) = 0 rad/s

Time taken to change velocity from w1 to w2 = 30 seconds

Angular acceleration is equal to the change in angular velocity to the time taken for making thing change

Hence, Angular acceleration

\frac{w_2 -w_1}{t} \\\frac{5-0}{30}\\0.167rad/s^2

3 0
1 year ago
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