answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexgriva [62]
1 year ago
10

Suggest one reason why the bricklayer needs a higher energy diet than the computer operator

Physics
1 answer:
sashaice [31]1 year ago
7 0

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

You might be interested in
John is running down the street and hears dogs barking in the distance. How do the sound waves change as John approaches the bar
FrozenT [24]

Answer:

The height of the sound waves increases

Explanation:

3 0
2 years ago
Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem. assuming air
expeople1 [14]
U = 0, initial vertical velocity

Neglect air resistance, and g = 9.8 m/s².

The time, t, required for the pen to attain a vertical velocity of 19.62 m/s is given by
19.62 m/s = 0 + (9.8 m/s²)*(t s)
t = 19.62/9.8 = 2.00 s

Answer:  2.0 s
8 0
1 year ago
A research group at Dartmouth College has developed a Head Impact Telemetry (HIT) System that can be used to collect data about
Olin [163]

Answer:

6.05 cm

Explanation:

The given equation is

2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)

The initial head velocity V₀ₓ =11 m/s

The final head velocity  Vₓ is 0

The accelerationis given by =1000 m/s²

the stopping distance = x-x₀=?

So we can wind the stopping distance by following formula

2 (-1000)(x-x₀)=[0^{2} -11^{2}]

x-x₀=6.05*10^{-2} m

       =6.05 cm

3 0
1 year ago
Military specifications often call for electronic devices to be able to withstand accelerations of 10 g. to make sure that their
trapecia [35]
The solution for this problem is:
(10 x 9.8) = 98.1 m/sec^2 acceleration. Time, to travel 9.4cm or (.094m.), at acceleration of 98m/sec^2

= sqrt(2d/a), = sqrt (98.1 m/sec^2/0.094m) = 32.3050619 sec per cycle

Frequency = (w/2pi), = 32.3050619/2pi
= 32.3050619/6.28318531
= 5.14 Hz would be the answer
6 0
1 year ago
An air-filled capacitor is formed from two long conducting cylindrical shells that are coaxial and have radii of 30 mm and 80 mm
Licemer1 [7]

Answer:

24

Explanation:

4 0
1 year ago
Other questions:
  • If you apply 100.0 N of force to lift an object with a single, fixed pulley, then what is the resistive force?
    8·1 answer
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. In a survey conduc
    14·1 answer
  • A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab is then inser
    7·1 answer
  • Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
    14·1 answer
  • n Section 12.3 it was mentioned that temperatures are often measured with electrical resistance thermometers made of platinum wi
    14·1 answer
  • A hydraulic lift is designed to lift cars up to 2000 kg in mass.If the lift under the car is 1.0 m by 1.2m and the area of the i
    14·1 answer
  • The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (
    12·1 answer
  • 8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
    7·1 answer
  • Consider the following spectrum where two colorful lines (A and B) are positioned on a dark background. The violet end of the sp
    8·1 answer
  • A. curious kitten pushes a ball of yarn at rest with its nose, displacing the ball of yarn 0.175 m in 2.00s. What is the acceler
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!