The desperate contestants on a TV survival show are very hungry. The only food they can see is some fruit hanging on a branch hi
gh in a tree. Fortunately, they have a spring they can use to launch a rock. The spring constant is 1000 N/m, and they can compress the spring a maximum of 30 cm. All the rocks on the island seem to have a mass of 400 g.a. With what speed does the rock leave the spring?b. If the fruit hangs 15 m above the ground, will they feast or go hungry?
1 answer:
You might be interested in
Answer:
The tension in the rope is 229.37 N.
Explanation:
Given:
Mass of the block is,
Coefficient of static friction is,
Angle of inclination is, °
Draw a free body diagram of the block.
From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.
Forces acting are and normal
. Now, there is no motion in the direction perpendicular to the inclined plane. So,
Consider the direction along the inclined plane.
The forces acting along the plane are and frictional force,
, down the plane and tension,
, up the plane.
Now, as the block is at rest, so net force along the plane is also zero.
Therefore, the tension in the rope is 229.37 N.
Answer:
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
Explanation:
We must work on this problem using the rotational equilibrium equations and then they compared the tension values that the cable supports.
Let's start with fixing a reference system on the hinge of the flag, we take as positive the anti-clockwise turn
They indicate the weight of the pole W₁ = 120 lb and a length of L = 9 ft, the weight of the man W₂ = 150, we assume that the cable is at the tip of the pole
- L + W₂ L + W₁ L / 2 = 0
T_{y} = W₂ + W₁ / 2
T_{y} = 120 + 150/2
T_{y} = 195 lb
we use trigonometry to find the cable tension
sin 30 = T_{y} / T
T = T_{y} / sin 30
T = 195 / sin 30
T = 390 lb
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
T < 500 lb