Answer: The frequency = 1714.3Hz
Explanation: The solution can be achieved by using doppler effect formula.
Since the source is moving toward the observer, the velocity of the observer will be positive.
Please find the attached file for the solution
Answer : The rate of heat transfer to the water is, 37.92 kJ/min
Explanation : Given,
Time = 10 min
Mass of water = 200 g
Latent heat of fusion of water = 334 J/g
Latent heat of vaporization of water = 2230 J/g
Now we have to calculate the rate of heat transfer to the water.

Now put all the given values in the above formula, we get:


Thus, the rate of heat transfer to the water is, 37.92 kJ/min
Answer:
<em>The object could fall from six times the original height and still be safe</em>
Explanation:
<u>Free Falling</u>
When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.
If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

Where v is the speed just before hitting the ground
If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

Solving for h

If the drop had occurred in the Moon, then

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g


This means the object could fall from six times the original height and still be safe
okay this is kinda easy
<u>What is the gravitational field strength on the moon?</u>
The Moon has a gravitational field strength of 1.6 N/kg.
Answer:
86.4 N downward
Explanation:
Force: This can be defined as the product of mass and acceleration of a body.
The S.I unit of Force is Newton(N).
The Expression of force is given as,
F = ma ................ Equation 1
Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.
Given: m = 72 kg, a = 1.2 m/s²
Substitute into equation 1
F = 72(1.2)
F = 86.4 N down ward.
Hence the force on the parachute harness = 86.4 N downward