answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
frozen [14]
2 years ago
11

A small object carrying a charge of -3.00 nc is acted upon by a downward force of 30.0 nn when placed at a certain point in an e

lectric field.
Physics
1 answer:
arlik [135]2 years ago
3 0
The working equation for this one is:

E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to

E = -30 nN/-3 nC
E = 10 nN/nC


You might be interested in
A container contains 200g of water at initial temperature of 30°C. An iron nail of mass 200g at temperature of 50°C is immersed
andriy [413]

Answer:

The final temperature is 31.94°

Explanation:

The mass of the water in the container m₁ = 200 g = 0.2 kg

The initial temperature of the water,  T₁₁ = 30°C

The mass of the iron, m₂ = 200 g = 0.2 kg

The temperature of the iron T₂₁= 50°C is immersed in the water,

The specific heat capacity of the water, c₁ = 4200 J/(kg·°C)

The specific heat capacity of the iron, c₂ = 450 J/(kg·°C)

Heat capacity relation is given by the formula;

Heat capacity Q = Mass, m × Specific heat capacity, c × Temperature change, (T₂ - T₁)

Given that energy can neither be created nor destroyed, and with the assumption that all the heat lost by the nail is gained by the water we have;

Heat lost by iron nail = Heat gained by the  water

m₁ × c₁ × (T₂ - T₁₁) = m₂ × c₂ × (T₂₁ - T₂)

Where, T₂ is the final temperature

0.2 kg × 4200 J/(kg·°C) × (T₂ - 30) = 0.2 kg × 450 J/(kg·°C) × (50° - T₂)

840·T₂ - 25200 = 4500 - 90·T₂

4500 + 25200 = 840·T₂ + 90·T₂

29700 = 930·T₂

T₂ = 29700/930 = 31.94°.

The final temperature = 31.94°.

4 0
2 years ago
A group of students collected the data shown below while attempting to measure the coefficient of static friction (of course, it
anzhelika [568]

Answer:

0.130

Explanation:

From the given data, the coefficient of static friction for each trial are:

1. 0.053

2. 0.081

3. 0.118

4. 0.149

5. 0.180

6. 0.198

The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

                                              = 0.779

So that;

the average coefficient of static friction = \frac{sum of coefficient of static friction}{number of trials}

                                              = \frac{0.779}{6}

                                              = 0.12983

The average coefficient of static friction is 0.130

8 0
1 year ago
An application of this principle is that a line mounted on transparent slide casts the same diffraction pattern as a dark film w
kifflom [539]

Explanation:

It is given that,

The distance between the first spot and the central minimum is, s = 0.007 cm

Length, l = 12 m

Wavelength, \lambda=6\times 10^{-7}\ m

We need to find the width of the hair. Using the condition of diffraction pattern as :

s=\dfrac{m\lambda l}{d}, d is the width of the hair

d=\dfrac{m\lambda l}{s}

d=\dfrac{1\times 6\times 10^{-7}\times 12}{0.007}

d = 0.00102

or

d=1.02\times 10^{-3}\ m

So, the width of the hair is 1.02\times 10^{-3}\ m. Hence, this is the required solution.

8 0
2 years ago
While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with the padded wall behind the
olga2289 [7]

Answer:

a.) F = 3515 N

b.) F = 140600 N

Explanation: given that the

Mass M = 74kg

Initial velocity U = 7.6 m/s

Time t = 0.16 s

Force F = change in momentum ÷ time

F = (74×7.6)/0.16

F = 3515 N

b.) If Logan had hit the concrete wall moving at the same speed, his momentum would have been reduced to zero in 0.0080 seconds

Change in momentum = 74×7.6 + 74×7.6

Change in momentum = 562.4 + 562.4 = 1124.8 kgm/s

F = 1124.8/0.0080 = 140600 N

6 0
2 years ago
Alex throws a 0.15-kg rubber ball down onto the floor. The ball’s speed just before impact is 6.5 m/s, and just after is 3.5 m/s
Jet001 [13]

Answer: Change in ball's momentum is 1.5 kg-m/s.

Explanation: It is given that,

Mass of the ball, m = 0.15 kg

Speed before the impact, u = 6.5 m/s

Speed after the impact, v = -3.5 m/s (as it will rebound)

We need to find the change in the magnitude of the ball's momentum. It is given by :

So, the change in the ball's momentum is 1.5 kg-m/s. Hence, this is the required solution.

Read more on Brainly.com - brainly.com/question/12946012#readmore

7 0
2 years ago
Other questions:
  • Determine the cutting force f exerted on the rod s in terms of the forces p applied to the handles of the heavy-duty cutter.
    11·2 answers
  • The pesticide DDT was first made by a chemical company in 1939 and became widely used worldwide. Evidence that DDT builds up in
    5·2 answers
  • Will two separate 50db sounds together constitute a 100db sound explain mathematical
    13·1 answer
  • A radio station's channel, such as 100.7 fm or 92.3 fm, is actually its frequency in megahertz (mhz), where 1mhz=106 hz and 1hz=
    7·2 answers
  • An ac generator has a maximum output emf of 215 V. What is the rms potential difference?
    14·1 answer
  • Which of the following is a characteristic of electromagnetic waves?
    8·2 answers
  • A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene
    5·1 answer
  • Of the three primary forms of subaerial volcanoes, ________ are large cone-shaped mountains that consist of alternating layers o
    5·1 answer
  • A battery powers a circuit for a small noisy fan. The fan’s motor gets warm as it turns. What energy transformations are taking
    6·2 answers
  • Un camión cargado, de masa 3000 kg, ha adquirido en la bajada de un puerto una velocidad excesiva de 108 km/h. Al ver una curva
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!