Answer: the answer is d
Explanation: there are not more than 10 violations within a twelve month period hope this helps
Answer:
a = 6.53 m/s^2
v = 11.5689 m/s
Explanation:
Given data:
engine power is 217 hp
70 % power reached to wheel
total mass ( car + driver) is 1530 kg
from the data given
2/3 rd of weight is over the wheel
w = 2/3rd mg
maximum force

we know that F = ma


the new power is 


solving for speed v

![v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}](https://tex.z-dn.net/?f=v%20%3D%200.7%20%5Cfrac%7B217%20%5B%5Cfrac%7B746%20w%7D%7B1%20hp%7D%5D%7D%7B1500%20%5Ctimes%206.53%7D)
v = 11.5689 m/s
Answer:
t = 2.68 x 10¹⁴ years
Explanation:
First we need to find the amount of energy that Sun produce in one day.
Energy = Power * Time
Energy of Sun in 1 day = (3.839 x 10²⁶ W)(1 day)(24 hr/1 day)(3600 s/ 1 hr)
Energy of Sun in 1 day = 3.32 x 10³¹ J
Now, the time required by the nuclear power generator, in years, will be:
Energy of power generator = Energy Sun in 1 day = 3.32 x 10³¹ J
3.32 x 10³¹ J = Power * Time
3.32 x 10³¹ J = (3.937 x 10⁹ W)(t years)(365 days/1 year)(24 hr/1 day)(3600 s/ 1 hr)
t = 3.32 x 10³¹ /1.24 x 10¹⁷
<u>t = 2.68 x 10¹⁴ years</u>
Answer: Weight only.
Explanation: Mass is a measure of the amount of matter in an object. Weight is a measure of the gravitational force exerted on the material in a gravitational field. Mass and weight are proportional to each other, with the acceleration due to gravity as the proportionality constant.
If a rock is transported from the moon to the earth, the mass is constant for the object but the weight will depends on the locations of the object. The gravitational acceleration would change because the radius and mass of the Moon is different from the Earth.
Thus, the object (rock) has <em>mass, m</em> both on the surface of the Earth and the surface of the Moon; but it will <em>weight</em> much less on the surface of the Moon as the Moon's surface gravity is 1/6 of the Earth.
Answer:
option (c)
Explanation:
mass of iron = 0.10 kg
mass of copper = 0.16 kg
rise in temperature, ΔT = 35°C
specific heat of iron = 450 J/kg°C
specific heat of copper = 390 J/kg°C
Heat by iron (H1) = mass of iron x specific heat of iron x ΔT
H1 = 0.10 x 450 x 35 = 1575 J
Heat by copper (H2) = mass of copper x specific heat of copper x ΔT
H1 = 0.16 x 390 x 35 = 2184 J
Total heat H = H1 + H2
H = 1575 + 2184 = 3759 J
by rounding off
H = 4000 J