The post mortem interval of a body enclosed in a plastic bag could be best estimated by the insects found in the body, in that case forensic science need to listen to what those little creatures have to say, insects could tell if the body has been moved from the crime scene, how long it´s been in an specific place, and how long it´s been since death until found, every group of insects can tell something different, from worms, arachnids to flyes, each one of them has a time to get into the body, so it could tell you for how long it´s been dead.
I believe its C-Mitochondrion.
It the powerhouse of the cell.
-Steel jelly
When evacuating victims and personnel currently facing danger to their lives, an establishment should have a safe evacuation routes. The evacuation route should be placed in the Exclusion Zone which means that it is a large site with obstructions and not safe until the safety area is reached. Another would be developing the Contamination Reduction Zone which is designed for individuals that are facing chemical dangers. Decontamination while inside the building is inadvised but would be applied in the arrival to the said zone. An access to potential routes should be available. Obstructions like locks, blocked doors are inadvisable. Routes should be free from items that are not needed within the area. Also, multiple routes that are separated from each other is recommended for evacuating numerous amount of people at the same time or when fire blocks one, there would be another choice available.
Answer: D. Less than 10%
Explanation:
Herbivores consume no more than 10% of living plant biomass.
Hope this helps!
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
