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ivanzaharov [21]
2 years ago
7

Find the z score that has 84.85% of the distributions area to its right

Mathematics
2 answers:
Norma-Jean [14]2 years ago
8 0
<span>If you have a TI calculator, then you can type in invnorm(1 - 0.628) You are subtracting the probability from 1 because the invnorm function finds the z-score given the probability to the left of the z-score</span>
omeli [17]2 years ago
5 0

The <em><u>correct answer</u></em> is:

1.03

Explanation:

We will use a z-table to do this.

84.85% = 84.85/100 = 0.8485; this is the value we look for in the middle of the table.  Once we find it, we see the number to the left is 1.00; above it we have 0.03.  This means that 1.00+0.03 = 1.03 is the z-score for this value.

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Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. if the semicircle
Nataly_w [17]
See the picture in the attached figure

we know that

[perimeter of the f<span>lower garden]=[7+10+10]+[pi*7/2]----> 27+10.99---> 37.99 ft

the answer is
37.99 ft </span>

5 0
2 years ago
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vector u is represented by the directed line segment RS and vector v is represented by the directed line segment OP. if R=(8,-2)
melamori03 [73]

The given points are

R=(8,-2) , S=(11,-6), O=(-3,-9), and P=(0,-13)

To find the value of u and v, we have to perform subtraction of the points . That is

u= RS = =

v = OP =  =

Since we get the same values of u and v , therefore the two vectors are equal .

8 0
2 years ago
As a computer technician, Andre makes $20 per hour to diagnose a problem and $25 per hour to fix a problem. He works fewer than
irinina [24]
For
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope

yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint

x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10

since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line


x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below

test point (4,5)

20(4)+25(5)≥200
80+125≥200
225≥200
true

4+5<10
9<10
true


so the ones that are true are

The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).








3 0
2 years ago
Read 2 more answers
A truck delivers 478 dozen eggs to stores in one day. Write an expression that finds the number of eggs the truck delivers in on
7nadin3 [17]
478*12= answer which the answer is: 5736
4 0
2 years ago
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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
FrozenT [24]

Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

Step-by-step explanation:

Let ABCD is the trapezoid, ( shown in below diagram)

In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7

Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

⇒ \frac{3+x}{18} = \frac{x}{11}

⇒  33 +11x = 18x

⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

But, AP= PD + DA

AP= 4\frac{5}{7}+3 =7\frac{5}{7}

Now, let PC =y,

⇒ \frac{7+y}{18} = \frac{y}{11}

⇒ 77 + 11y = 18y

⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



7 0
2 years ago
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