See the picture in the attached figure
we know that
[perimeter of the f<span>lower garden]=[7+10+10]+[pi*7/2]----> 27+10.99---> 37.99 ft
the answer is37.99 ft </span>
The given points are
R=(8,-2) , S=(11,-6), O=(-3,-9), and P=(0,-13)
To find the value of u and v, we have to perform subtraction of the points . That is


Since we get the same values of u and v , therefore the two vectors are equal .
For
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope
yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint
x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10
since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line
x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below
test point (4,5)
20(4)+25(5)≥200
80+125≥200
225≥200
true
4+5<10
9<10
true
so the ones that are true are
The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).
Answer: The length of segments between this point and the vertices of greater base are
and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,

Let, DP =x
⇒ 
⇒ 33 +11x = 18x
⇒ x = 33/7= 
Thus, PD= 
But, AP= PD + DA
AP= 
Now, let PC =y,
⇒ 
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18