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vichka [17]
2 years ago
9

A home costing 540,000 is worth 588,000 two years later. What is the one year appreciation rate

Mathematics
2 answers:
gulaghasi [49]2 years ago
5 0

Answer:

A home costing $540,000 is worth $588,000 two years later. What is the one-year appreciation rate? 4.4% is the answer

Step-by-step explanation:


Alenkinab [10]2 years ago
3 0

Answer:

the answer is 48,000

Step-by-step explanation:

its simple you just subtract the bigger number to the smaller number

588,000- 540,000

=48,000 (sorry if it wrong i am not exactly sure sorry please forgive me)



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Which statements are true regarding the transformation? Check all that apply. EF corresponds to E'F'. FG corresponds to G'D'. ∠E
8090 [49]

Answer: A,C,D,F

Step-by-step explanation:

3 0
2 years ago
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Mikayla is training for a half-marathon. At the beginning of her training, she is able to run 2 miles without stopping. Her goal
ivanzaharov [21]

Alright, lets get started.

At the beginning of her training, she is able to run 2 miles without stopping means 2 will be in the addition when we will write the equation for her running miles.

Her goal is to increase her distance by three quarters of a mile each week.

Means in first week, she will add the distance = \frac{3}{4} miles

Suppose she runs x weeks, so shee will add distance = \frac{3}{4}x

So, suppose she runs total number of miles = d, then

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Where d is total numer of miles she runs

x is number of weeks    :   Answer

Hope it will help :)


5 0
2 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.
zvonat [6]

Answer:

x=-2.38

x=-4.62


Step-by-step explanation:

The question is  (2x+3)^2+8(2x+3)+11=0

<em>We let u=2x+3, so the equation becomes:</em>

u^2+8u+11=0

Where a=1, b=8, c=11


Putting it in the quadratic formula, we have:

<u>Quadratic formula:</u> \frac{-b+-\sqrt{b^2-4ac} }{2a}

Substituting we have: \frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }


<em>We let u=2x+3, so x is:</em>

<em>u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38</em>

<em>and</em>

<em>u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62</em>


The solutions of the equation is x=-2.38 (rounded to 2 decimal places), and x=-4.62 (rounded to 2 decimal places)

6 0
2 years ago
Ms. Nina has 10 lbs of 25% sugar syrup. How much water does she need to add to make 10% sugar syrup
Inessa [10]
10*0.25=2.5
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Nina need to add 15 lbs of water
7 0
2 years ago
For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
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x=10

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Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
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2 years ago
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