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2 years ago

11

Rent for a 3-bedroom apartment is regularly 936 per month. Apartment management is now offering one month free for 12- month lea

se. If you sign a one year lease and apply the free month equally across months, how much is your new monthly amount?

1 answer:

adelina 88 [10]2 years ago

8 0

Answer:

$858.

Step-by-step explanation:

We have been given that rent 3-bedroom apartment is regularly 936 per month.

The management is now offering one month free for 12- month lease. When we will sign the lease, we will pay the rent for 11 months. So our rent for 1 year after signing the lease will be:

$\text{Rent of the apartment for 1 year after signing the lease}= 11\times 936$

$\text{Rent of the apartment for 1 year after signing the lease}= 10296$

Let us find new monthly amount by dividing 10296 by 12.

$\text{The new monthly amount}=\frac{10296}{12}$

$\text{The new monthly amount}=858$

Therefore, our new monthly amount will be $858.

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Answer:

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Step-by-step explanation:

We use z scores to answer these questions. The formula for a z score is

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For part a,

We want P(X > 43):

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Using a z table, we see that the area under the curve to the left of this is 0.2514. However, we want the area to the right; this means we subtract from 1:

1 - 0.2514 = 0.7486

For part b,

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z = (45-44)/1.5 = 1/1.5 = 0.67

Using a z table, the area under the curve to the left of z = -1.3 is 0.0968. The area under the curve to the left of z = 0.67 is 0.7486.

The area between them is 0.7486 - 0.0968 = 0.6518.

For part c,

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Answer:

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Step-by-step explanation:

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Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

$t = 3.054$

4

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

5

The conclusion is

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The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

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2 years ago