Area=legnth times width=31
the frame must go around the frame with equal legnth, x
so
the total area (meaning the frame +picture) is 5+x by 6+x
31=(5+x)(6+x)
expand
31=30+11x+x^2
minus 31 both sides
0=-1+11x+x^2
x^2+11x-1=0
answer is third one
The shape of the graph is similar to the letter W; however, the region of interest will lie on the right of the origin, which means only the right half of the W(a negative number of cans cannot be produced). The profit produced will be maximized if the number of cans produced is greater than 3. The company will be at a loss if the number of cans produced is near 2.5. The break even situations are present if the company produces 2 or 3 cans.
Answer:
Volume of the right pyramid = 288 m²
Step-by-step explanation:
Volume of the pyramid = 
From the ΔAOB,
By Pythagoras theorem,
AB² = AO² + OB²
(6√2)² = AO² + (6)²
72 = AO² + 36
AO = √(36) = 6 m
Since base of the pyramid is a square so area of the base = (Length × Width) = (side)²
Now volume of the pyramid = ![\frac{1}{3}[(Length)(width)]\times height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%5B%28Length%29%28width%29%5D%5Ctimes%20height)
= 
= 288 m²
Therefore, volume of the right pyramid is 288 m².
Answer:
The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).
We are to plot D on the graph.
Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.
Step-by-step explanation:
