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2 years ago

Which matrix can be multiplied to the left of a vector matrix to get a new vector matrix ?

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

5 0

Answer: The answer is (B).

Step-by-step explanation: We are given four options and we are to select which matrix can be multiplied to the left of a vector matrix to get a new vector matrix. The order of a vector matrix is either n × 1 or 1 × n.

For (A): The order of the matrix is 2 × 1. If we multiply this matrix by a vector matrix of order 1 × 2, then the resulting matrix will be of order 2 × 2, which is not a vector matrix.

For (B): The order of the matrix is 3 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 3 × 1, which is a new vector matrix.

For (C): The order of the matrix is 2 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 2 × 1, which is a vector matrix of order same as before.

For (D): The order of the matrix is 1 × 2. If we multiply this matrix by a vector matrix of order 2 × 1, then the resulting matrix will be of order 1 × 1, which is a not vector matrix.

Thus, the correct option is (B).

Nataliya [291]2 years ago

3 0

Answer:

<h2>the answer is option c </h2><h2></h2><h2></h2>

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(2.5 points) The probability that an airplane accident which is due to structural failure is diagnosed correctly is 0.85 and the

Nikitich [7]

Answer: 0.51

Step-by-step explanation:

This is a conditional probability. The first event is the airplane accident being caused by structural failure. The probability of it being due to structural failure is 0.3 and the probability of it not being due to structural failure is 0.7. The second event involves the diagnosis of the event. If a plane fails due to structural failure, the probability that it will be diagnosed and the results will say it was due to structural failure is 0.85, and the probability that the diagnosis is unable to identify that it was because of a structural failure is 0.15. If the plane were to fail as a result of some other reason aside structural failure, the probability that the diagnosis will show that it was as a result of structural failure is 0.35 and the probability of the diagnosis showing that is is not as a result of structural failure is 0.65. To find the probability that an airplane failed due to structural failure given that it was diagnosed that it failed due to some malfunction, this is the equation;

p = (probability of plane failing and diagnosis reporting that the failure was due to structural failure)/ (probability of diagnosis reporting that failure was due to structural failure)

p = (0.3*0.85)/((0.3*0.85) + (0.7*0.35))

p = 0.51

4 0

2 years ago

A zookeeper is monitoring the population of birds. The flock needs to have exactly three times more females than males to thrive

KIM [24]

Answer:

The constraints are

$0 < x\leq 20$ and $0 < y\leq 60$

Step-by-step explanation:

Let

x ----> represent the number of male birds

y ----> represent the number of female birds

we know that

The flock needs to have exactly three times more females than males to thrive

$y=3x$ ----> equation A

The zoo only has room for a maximum of 20 male birds

$0 < x\leq 20$ ----> inequality B

we know that

The maximum number of male birds is 20

For x=20

substitute in the equation A

$y=3(20)=60$

The maximum number of female birds is 60

$0 < y\leq 60$ ----> inequality C

therefore

The constraints are

$0 < x\leq 20$ and $0 < y\leq 60$

4 0

2 years ago

The cost of insurance on a house is directly proportional to the area of the house.Samhas a 2,500 square-foot house and pays a m

DochEvi [55]

Answer:

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7 0

2 years ago

The glee club has $90 to spend on pens and pencils. Each pen costs $0.75 and each pencil costs $0.15. Let x represent the number

brilliants [131]

Answer:

part A; B and Part B; pencils

Step-by-step explanation:

you want to find out how many pens and pencils you cn buy with that 90$ so you want to do

.75y+.15x=90

pens=50

pencils=50

but you want to add .75+.15 which = .90

then you divide 90/.90

and that equals 100

then split it up and each gets 50

4 0

2 years ago

Read 2 more answers

Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure.

Alona [7]

Answer:

Step-by-step explanation:

Hello!

The monitoring system warn the driver when the tire pressure of the vehicle is 28% below target pressure.

Be X: target tire pressure of a certain car (pounds per square inch)

X= 28 psi

If the monitoring system will warn the driver when the pressure is 28% below the target pressure: X-0.28X

First step, you have to calculate the 28% of 28psi

28*0.28= 7.84

Second step, is to subtract the calculated 28% to the target pressure:

28 - 7.84= 20.16

The TPMS will trigger a warning at 20.16 psi.

If X~N(μ;σ²)

μ= 28psi (since the average is on target, then the target pressure for the car will be the average value of the distribution)

σ= 3psi

P(X≤20.16)

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now you have to look for the corresponding value of probability using the Z-table. Since the value is negative you have to the use the left entry of the Z-table, in the first column you'll find the integer and first decimal of the value -2.6- and in the first row you'll find the second decimal value -.-1

The value of probability that corresponds to -2.61 is:

P(Z≤-2.61)= 0.005

You have to calculate the probability of inspecting a tire at random and it being inflated within recommended range, symbolically this is:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Calculate both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

The probability of the tire being inflated within recommended inflation range is 0.498.

I hope this helps!

5 0

2 years ago