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2 years ago

Triangle BCD was dilated using the rule . What are the values of the unknown measures?

Mathematics

2 answers:

SpyIntel [72]2 years ago

7 0

Answer:

CBD= 95 degrees

CQ=6

BD=11

a_sh-v [17]2 years ago

3 0

Answer:

the answers are (95) (6) and (11)

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D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she

Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:

$\frac{i}{e}=\frac{5}{3}$

Let's multiply both sides by e. This yields:

$i=\frac{5}{3}e$

We know that when the income is <em>increased</em> by 5000 and the expenditures are <em>decreased </em>by 3000, the new ratio is 5:2. So, we can write the following proportion:

$\frac{i+5000}{e-3000}=\frac{5}{2}$

Let's multiply both sides by $(e-3000)$ :

$i+5000=\frac{5}{2}(e-3000)$

Since we know that $i=\frac{5}{3}e$ , substitute:

$\frac{5}{3}e+5000=\frac{5}{2}(e-3000)$

So, let's solve for the expenditures. Distribute the right:

$\frac{5}{3}e+5000=\frac{5}{2}e-7500$

Subtract $\frac{5}{2}e$ from both sides:

$-\frac{5}{6}e+5000=-7500$

Subtract 5000 from both sides:

$-\frac{5}{6}e=-12500$

Multiply both sides by -6/5. So, the expenditures are:

$e=\text{Rs }15000$

We can use the original ratio to find Sunayana's income:

$i=\frac{5}{3}e$

Substitute 15000 for e. Evaluate:

$i=\frac{5}{3}(15000)=\text{Rs }25000$

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

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2 years ago

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Atraeus is solving the quadratic equation by completing the square.

arsen [322]

OK so the value of A would be 7 because as you can see from the second to third step, Atraeus factored out 7 from both terms!

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2 years ago

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A simple random sample of the weights of 59 green candies has a mean of 0.8635 g. Assume that σ is known to be 0.0565 g. Assume

mina [271]

Solution: We are given:

$\mu=0.8635$

$\sigma=0.0565$

$n=59$

We need to find the test statistic in order to test the claim that the mean weight of all green candies is equal to 0.8535

We know that the test statistic is:

$z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}$

$=\frac{0.8535-0.8635}{\frac{0.0565}{\sqrt{59}}}$

$=\frac{-0.01}{0.007355673}$

$=-1.36$

Therefore, the test statistic is $z=-1.36$

Hence the option -1.36 is correct.

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2 years ago

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Select the correct answer.

Mademuasel [1]

Answer:

26 rooms

Step-by-step explanation:

$y = 2.315x + 4.084\\64=2.315x+4.084\\x = (64-4.084)/2.315\\x = 25.88$

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The penny size d is given by the literal equation d = 4n - 2, solve for n

Tresset [83]

D = 4n - 2
+2 +2

d + 2 = 4n

Divide both sides by 4

n = d + 2 / 4

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2 years ago

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