Question

The function f(x)=x^5+(x+3)^2 is used to create this table

Answer 1

Answer:

The value which completes the table is:

                         3

Step-by-step explanation:

We are given a odd-degree( degree-5) function f(x) by:

              $f(x)=x^5+(x+3)^2$

  Now, we are asked to complete the table.

i.e. we are asked to find the value of the function f(x) when x= -1

So, when x= -1 we have:

$f(-1)=(-1)^5+(-1+3)^2\\\\\\f(-1)=-1+(2)^2\\\\\\i.e.\\\\\\f(-1)=-1+4\\\\\\i.e.\\\\\\f(-1)=3$

Hence, the complete table is given by:

            x                f(x)

           -2                -31

           -1                    3

            0                   9

             1                   17

The answer is: 3

Answer 2

Answer:

3

Step-by-step explanation:

To find the value, substitute x = -1 into the equation and simplify.

$f(-1) = (-1)^5 + (-1+3)^2\\f(-1) = -1 + (2)^2\\f(-1) = -1 + 4\\f(-1) = 3$