Answer:
Option C is right
Step-by-step explanation:
Given are two samples
I group has sample size 90, mean = 9.2 and std dev =0,.37
II group has sample size 70, mean = 7.3 and std dev = 0.58
we find that mean difference i.e. difference between mean hours of sleep between two groups
= 9.2-7.3 = 1.9
Std error for difference = 0.0620
Since sample size is sufficiently large we can use Z critical for 99%
i.e. 2.58
Margin of error =±2.58(0.062)
=0.16
Hence confidence interval 99% for difference in hours of sleep
= (1.9-0.16,1.9+0.16)
=(1.74, 2.06)
Find h(x)
f(x)+g(x)=5x+15+4x+20=9x+35
ok so if gertrude works 4
f(x)=5x+15
f(4)=5(4)+15
f(4)=35
if we input 4 for x in f(x) to find how much made togethe rin 4 hours
h(4)=9x+35
h(4)=9(4)+35
h(4)=36+35
h(4)=71
split evenly?
71/2=35.5
frankalone=35 for 4 hours
frankwithgertrued=35.5 for 4 hours
slightly bettewr with gerturde
To determine the cost of each item, we need to set up equations. From the problem statement, we have three unknowns so we need three equations. We set up equations as follows:
let x cost of small pizzas
y cost of soda
z cost of salad
two small pizzas, a liter of soda, and a salad cost $14
2x + y + z = 14
one small pizza, a liter of soda, and three salads cost $15
x + y + 3z = 15
three small pizzas, a liter of soda, and two salads cost $22
3x + y + 2z = 22
Solving for x, y and z, we will have:
x = $ 5
y = $ 1
z = $ 3
The error.....Kelvin just figured the 60% markdown cost...not the final price
the final price would be : 30.65 - 0.60(30.65) = 30.65 - 18.39 = 12.26
so 12.26 is the final price
or another way to do this is : if it is marked down 60%, then u r actually paying 40%......0.40(30.65) = 12.26
d/dx (2 x^2 y + y = 2x + 13)
4xy + 2x^2 y' + y' = 2
4xy + y'(2x^2 + 1) = 2
y' = (2- 4xy)/(2x^2 +1)
<span>ow we can use this in a linear equation for a slope
Ty = -5x/8 +5(3)/8 +8/8
= -5x/8 +(15+8)/8
= -5x/8 +23/8
this will gives us an approximation at x=2.8 now</span>
