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2 years ago

Find all real zeros of the function y=-5x-7

Mathematics

2 answers:

Yakvenalex [24]2 years ago

5 0

Answer:

x=1 2/5

Step-by-step explanation:

Replace y with 0 and solve for x.

Ahat [919]2 years ago

4 0

Answer: The required zero of the given function is x = -1.4.

Step-by-step explanation: We are given to find all the real zeroes of the following function :

$y=-5x-7~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Since the given function is linear, so it will have only one real zero.

Also, the zeroes of a function y = f(x) is given by f(x) = 0.

So, the zero of the given function (i) is

$y=0\\\\\Rightarrow -5x-7=0\\\\\Rightarrow 5x=-7\\\\\Rightarrow x=-\dfrac{7}{5}\\\\\Rightarrow x=-1.4.$

Thus, the required zero of the given function is x = -1.4.

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Answer:

Step-by-step explanation:

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2 years ago

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borishaifa [10]

Step-by-step explanation:

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2 years ago

Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression

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2 years ago

Read 2 more answers

Five minivans and three trucks are traveling on a 3.0 mile circular track and complete a full lap in 98.0, 108.0, 113.0, 108.0,

Alex

Answer:

The time-mean speed of the minivans is of 105.8 seconds.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

Five minivans, times of: 98.0, 108.0, 113.0, 108.0, 102.0, in seconds.

Thus, the mean is:

$M = \frac{98 + 108 + 113 + 108 + 102}{5} = 105.8$

The time-mean speed of the minivans is of 105.8 seconds.

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2 years ago

What is the following simplified product? Assume x greater-than-or-equal-to 0 (StartRoot 10 x Superscript 4 Baseline EndRoot min

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Answer:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

Step-by-step explanation:

To find:

Simplified product of:

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})$

Solution:

First of all, let us have a look at some of the formula:

1. $(a+b) (c+d) = ac+bc+ad+bd$

2. $a^b\times a^c =a^{b+c }$

3. $\sqrt{a^{2b}} = \sqrt{a^b.a^b}=a^b$

4. $\sqrt a \times \sqrt b = \sqrt{a\times b}$

Now, let us apply the above formula to solve the given expression.

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\\Rightarrow(\sqrt{10x^4})(2\sqrt{15x^4})+(\sqrt{10x^4})(\sqrt{3x^3})-(x\sqrt{5x^2})(2\sqrt{15x^4})-(x\sqrt{5x^2})(\sqrt{3x^3})\\\\\Rightarrow2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\\Rightarrow\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

The answer is:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

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2 years ago