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2 years ago

ANSWER ASAP!!!!!

Mathematics

1 answer:

schepotkina [342]2 years ago

8 0

Answer:

{CM} {CD} {CW} {MC} {MD} {MW} {DC} {DM} {DW} {WC} {WM} {WD}

Step-by-step explanation:

The sample space is all the possible results that can be obtained from a randomized experiment.

In this case, the experiment is to select two chocolates out of 4.

If we have 4 chocolates of different types {C, M, D, W}

and we select 2, then (taking into account the order in which she eats the chocolates} the possible results are:

{CM} {CD} {CW} {MC} {MD} {MW} {DC} {DM} {DW} {WC} {WM} {WD}

There are 12 possible results for this experiment.

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Do males spend more time playing online games than females? A random sample of 100 males and females was selected. Let mꜰ be the

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Answer:

A random sample of 100 male and females was selected. Let muf be the population mean number of hours spent playing online games for females and let mum be the population mean number of hours spent playing online games for males.

Step-by-step explanation:

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2 years ago

Which value represents |7.8|?

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Since absolute value is just taking the positive value of whatever you put in the function, it is 7.8 as well. Also, absolute value can be described as the distance from 0 on the number line. 7.8 is 7.8 "units" away from 0, thus meaning it is equal to 7.8.

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The coordinates of the vertices of the triangle are (–8, 8), (–8, –4), and . Consider QR the base of the triangle. The measure o

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The coordinates of the vertices of the triangle are
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2 years ago

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Find the integer a such that a.a ≡ 43 (mod 23) and −22 ≤ a ≤ 0.

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2 years ago

Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The

Harlamova29_29 [7]

Answer:

$t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923$

The degrees of freedom are

$df=20+20-2=38$

And the p value is given by:

$p_v =2*P(t_{38}>2.923) =0.0058$

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$