Answer:
They concluded that these antibodies were a) Globular proteins
Explanation:
Globular proteins are known to be water-soluble, spherical in shape and to be polypeptides as well. Compared to the other options provided, the selected one is the most correct.
Answer:
III. Condensation of chromosomes begins.
I. Synapsis occurs.
II. Crossing-over is completed.
IV. Separation of homologous chromosomes begins
Explanation:
The prophase I of meiosis I begins with the condensation of chromosomes. The process of compaction makes the individual chromosomes visible and the stage is called leptotene.
Leptotene is followed by zygotene of prophase I during which the homologous chromosomes are paired together. The process is mediated by the synaptonemal complex. As the homologous chromosomes are paired, each pair is visible as a tetrad as each of the chromosomes of a pair has two sister chromatids.
The exchange of part of chromatids occurs during crossing over. Crossing over is the event of the pachytene stage of prophase I. After crossing over, the homologous chromosomes begin to separate from each other during diplotene but stay paired at the points of crossing over. These points are called chiasmata. Diakinesis of prophase I is marked by the dissolution of chiasmata.
Answer:
Cross each to a rabbit who you know is homozygous - i.e. a white rabbit. If there are any white offspring you know this is the heterozygote.
Explanation:
Heterozygous individuals are those with 2 different alleles of a gene. Homozygous individuals have have 2 alleles that are the same.
Imagine the allele for coat color is B black, or b white. If you cross 2 individuals who are homozygous for the black gene (BB), they would only produce black rabbits in the F1 (BB). If you cross the F1, they could only produce BB rabbits in the F2.
However, if you cross a heterozygous rabbit with a homozygous black rabbit (Bb x BB), you would get either BB or Bb rabbits in the F1. However, intercrossing them could produce BB, Bb, or bb rabbits. Therefore, white rabbits can be produced.
You know that white rabbits are bb. So if you are unsure about the genotype of the black rabbit, you can cross it with a white rabbit (either BB x bb or Bb x bb). If any white rabbits appear in the F1, you know there must be a b allele in the black rabbit genotype, so that rabbit must be heterozygous.
The given question is incomplete as options are not provided, however the options are as follows :
- Golgi bodies
-lysosomes
-microvilli
-multiple nuclei
Answer:
The correct answer is - golgi bodies.
Explanation:
Goblet cells and glandular epithelial cells are cells that produce and secretes a specific type of products that are termed as the mucin to protect the skin and layer mucous membrane they place.
These cells are characterized by a large amount of Golgi body and endoplasmic reticulum as they are involved in the exocytic pathway which means they secrete, glycoproteins, mucin, and other substances. Golgi bodies needed to modify, synthesis, and secretion.
Thus, the correct answer is - golgi bodies.
<span>The structure of a paramecium that holds a "reserve copy" of all the cell's genes is the micro nucleus.
</span>The micro nucelus is one of the <span>two kinds of </span>nuclei the paramecium has. The other is the<span> large ellipsoidal </span>nucleus<span> called a macronucleus. Every paramecium must have at least one small </span>nucleus<span> called a </span>micronucleus. The micronucleus is a storage site for the germline genetic material of the organism.
