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Nuetrik [128]
2 years ago
11

Alex the electrician needs 34 yards of electrical wire to complete his job. He has a coil of wiring in his workshop. The coiled

wire is 18 inches in diameter and is made up of 21 circles of wire. Will this coil be enough to complete the job? Let Pi be 3.14.
Mathematics
1 answer:
bogdanovich [222]2 years ago
8 0

Answer: This coil will not be enough to complete the job.

Step-by-step explanation:

The circumference of the coil of wiring can be calculated with:

C=2\pi r

Where r is the radius and \pi=3.14

The radius can be calculated by dividing the diameter by 2. Then:

r=\frac{18in}{2}\\\\r=9in

Convert 9 inches to yards (1 yard=36 inches):

(9in)(\frac{1yd}{36in})=0.25yd

Substitute this radius into the formula:

C=2(3.14)(0.25yd)\\C=1.57yd

Since there are 21 circles of wire, you need to multiply C=1.57yd by 21:

C_T=(1.57yd)(21)=32.97yd

The coil has 32.97 yards of wire and Alex needs 34 yards, therefore, this coil will not be enough  to complete the job.

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Answer:

f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252

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Step-by-step explanation:

Given

f(x) = 3x^2 + 9

g(x) = \dfrac{1}{3}x^2 - 9

Required

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Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

f(x) = 3x^2 + 9

f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9

f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9

Expand Brackets

f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9

f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9

f(g(x)) = \frac{1}{3}x^4 - 9x^2 - 9x^2 + 243 + 9

f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252

Calculating g(f(x))

g(x) = \dfrac{1}{3}x^2 - 9

g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9

g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9

g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9

Expand Brackets

g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9

g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9

g(f(x)) = 3x^4 + 18x^2 + 18

Checking for inverse functions

f(x) = 3x^2 + 9

Represent f(x) with y

y = 3x^2 + 9

Swap positions of x and y

x = 3y^2 + 9

Subtract 9 from both sides

x - 9 = 3y^2 + 9 - 9

x - 9 = 3y^2

3y^2 = x - 9

Divide through by 3

\frac{3y^2}{3} = \frac{x}{3} - \frac{9}{3}

y^2 = \frac{x}{3} - 3

Take square root of both sides

\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}

y = \sqrt{\frac{x}{3} - 3}

Represent y with g(x)

g(x) = \sqrt{\frac{x}{3} - 3}

Note that the resulting value of g(x) is not the same as g(x) = \dfrac{1}{3}x^2 - 9

<em>Hence, f(x) and g(x) and not inverse functions</em>

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Answer:

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Step-by-step explanation:

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The value of the test statistics is 0.975.

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