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Basile [38]
2 years ago
13

Olivia is cutting a 1 \dfrac12 \text{ m}1 2 1 ? m1, start fraction, 1, divided by, 2, end fraction, space, m by \dfrac34\text{ m

} 4 3 ? mstart fraction, 3, divided by, 4, end fraction, space, m piece of rectangular paper into two pieces along its diagonal. Find the area of each of the pieces.
Mathematics
2 answers:
ira [324]2 years ago
5 0

Answer:

9/16

Step-by-step explanation:

lubasha [3.4K]2 years ago
4 0

"169 A" is answer than k y o u

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Is AB parallel to Bo? Explain.
Svetradugi [14.3K]

Answer:

AB parallel to CD because both lines have a slope of

of 4/3

Step-by-step explanation:

The question is not complete, there is no graph.

A graph for the question is attached below.

From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).

Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

(x_1,y_1)\ asnd\ (x_2,y_2).\ The\ slope \ is\ given\ as:\\\\Slope(m)=\frac{y_2-y_1}{x_2-x_1}

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-3)}{0-(-3)}=\frac{1+3}{0+3}=\frac{4}{3}

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-5)}{3-0}=\frac{-1+5}{3}=\frac{4}{3}

Therefore AB parallel to CD because both lines have a slope of

of 4/3

7 0
2 years ago
An adult meerkat weighed 0.776 kilograms . this is 7.47 hectograms more than the weight of a baby meerkat . how much dose a baby
Firlakuza [10]
Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg
7 0
2 years ago
Read 2 more answers
PI-3.
Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

x=2q_1+1

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

x=3q_2+1

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

x=7q_6

This means x-1 is divisible by 2, 3, 4, 5 and 6 without remainder, so

x-1=2\cdot 3\cdot 2\cdot 5n=60n

Hence,

x=60n+1, \ n\in N

The smallest amount of money they could have raised is $301, because

x=60\cdot 5+1=301 is divisible by 7.

Now, the number x=60n+1 should be divisible by 7 and must be greater than 500.

So,

60n+1>500\\ \\60n>499\\ \\n>8

When n = 9,

x=60\cdot 9+1=541 is not divisible by 7.

When n = 10,

x=60\cdot 10+1=601 is not divisible by 7.

When n = 11,

x=60\cdot 11+1=661 is not divisible by 7.

When n = 12,

x=60\cdot 12+1=721 is divisible by 7.

B. The least amount of money they could have raised is $721

7 0
2 years ago
Read 2 more answers
The singing club keeps sheet music in files. Each file holds 12 sheets. Of all the club's music, 2/3 fit into 3 files. How many
laila [671]
1 file -> 12 sheets

Now for 3 files -> 3*12 = 36 sheets, it takes up 2/3 of the total

So the total number of sheets: 36 / (2/3) = 54
6 0
2 years ago
Phineas is the lead research scientist in a lab and responsible for ordering supplies and equipment. The lab is out of petri dis
natita [175]
Ax+by=185
12x+by=185
answer is 12x+y=185
4 0
2 years ago
Read 2 more answers
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