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Dennis_Churaev [7]
2 years ago
7

A survey asks teachers and students whether they would like the new school mascot to be a shark or a moose . this table shows th

e results .
A person is randomly selected from those surveyed
Are being a student and preferring “shark” independent events ? Why or why not ?

Mathematics
2 answers:
harkovskaia [24]2 years ago
4 0

Answer: the answer is B

Step-by-step explanation: apex

vovikov84 [41]2 years ago
4 0

Answer:

No, they are not independent because P(student)= 0.87 and P(student/shark)=0.95

Step-by-step explanation:

Just took the quiz on Apex :)

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PLS HALP ME!!!!!! You have $6.50 to make copies. Each copy costs $0.45. Write and solve an inequality that represents the number
serious [3.7K]

Step-by-step explanation:

Variable x = number of copies

6.50 <= 0.45x

Divide both sides by 0.45

6.50 ÷ 0.45 <= 0.45x ÷ 0.45

14.4444.... <= x

No more than 14 copies

6.50 <= 0.45x

6.50 <= 0.45(14.444)

7 0
2 years ago
Suppose that the Department of Transportation would like to test the hypothesis that the average age of cars on the road is less
dimulka [17.4K]

Answer:

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

z_{critc}= -1.64

Since our calculates values is lower than the critical value we have enough evidence to reject the null hypothesis at 5% of significance. And the best conclusion for this case is:

B. Since the test statistic is less than the critical value, we can conclude that the average age of cars on the road is less than 12 years.

Step-by-step explanation:

Data given and notation  

\bar X=10.6 represent the sample mean

\sigma=4.1 represent the population standard deviation

n=45 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 12, the system of hypothesis would be:  

Null hypothesis:\mu \geq 12  

Alternative hypothesis:\mu < 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

Critical value

For this case since w ehave a left tailed distribution we need to find a value who accumulates 0.05 of the area on th left in the normal standard distribution, and we can use the following excel code:

"=NORM.INV(0.05,0,1)"

z_{critc}= -1.64

Conclusion  

Since our calculates values is lower than the critical value we have enough evidence to reject the null hypothesis at 5% of significance. And the best conclusion for this case is:

B. Since the test statistic is less than the critical value, we can conclude that the average age of cars on the road is less than 12 years.

3 0
2 years ago
Which graph represents 2x-5y&lt;15?
Rzqust [24]
The graph would look something like this

6 0
2 years ago
Read 2 more answers
The price of a 200000 home listed by remax was reduced by 1/20. What is the new price?
expeople1 [14]
Hello,

shall we begin?

1o = 1/20 = 1:20 = 0,05
2o = 200.000 price of home

New price of home:
= 200,000 - ( 200,000 * 0,05) 
= 200,000 - 10,000
= 190,000


<span>Answer: 190,000   Good studies !!!</span>
4 0
2 years ago
If staff salaries were $32,000/month last year and $47,000/month this year, what is the percentage labor cost increase? (Round t
NeX [460]
100(47000-32000)/32000=47%  (to nearest percent)
6 0
2 years ago
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