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Dafna1 [17]
2 years ago
9

Which of the following statements about action potentials in a given neuron is false? a. All action potentials for a given neuro

n are identical in magnitude.b. All action potentials for a given neuron are identical in duration.c. Action potentials are propagated down the length of the axon.d. Movement of ions during the action potential occurs mostly through the sodium pump.e. The frequency of action potentials, not their size, is the meaningful signal.
Biology
1 answer:
BabaBlast [244]2 years ago
3 0

Answer:

They are propogated down the length of the dendrite

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Write a creative paragraph describing the “thought” process of the first cell that describes how this symbiosis occured. (Of cou
Anarel [89]

Answer:

just learned about this in ap bio haha

Explanation:

Wow, that's such a cool prokaryotic cell. It looks so delicious, I wonder if I can eat it.

"Hey, cell, can I eat you?"

"No, you cannot."

"Please? I would love to have your energy-making properties!"

"How would I benefit from this? It seems like you're being parasitic."

"I would help you, by giving you protection and a safe home. You would give me energy. It seems more like an endosymbiotic relationship to me!"

"Fine, you can ingest me."

I'm so glad they let me eat them, they were so yummy. I can even create energy now, and I have a powerhouse inside me! This is so cool, maybe I should eat that other cell with photosynthetic properties.

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6 0
2 years ago
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There are six people in the Fisher family. Olivia and Marcus are the parents. They have four children: Violet, Nathan, Jonas, an
Trava [24]
<span> Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles.
Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype.
Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons.
Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples.
Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous.
PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper.
Pheww... done.. Hope this helps! :)<span>
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The fusion of the sperm with the egg results in the formation of a zygote that develops into a new offspring. Twins refers to the two offspring which are a result of the same pregnancy. They are of two types. Monozygotic twins are a result of the single zygote (formed by the fusion of one egg with a single sperm) spiltting into two embryos forming the identical twins. Dizygotic twins are a result of two eggs fertilized with two different sperms forming the fraternal twins.

Identical twins are genetically simliar. The genetic material is derived from the same embryo and thus, the DNA of the identical twins are nearly identical. The spilitting of the embryo formed results in the separation of the same genetic material or identical DNA getting incorporated into the twins making them look alike in majority of the cases.

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2 years ago
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What purpose is served by the loss of an -H and -OH end from two molecules as they join together during dehydration synthesis
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The loss of the hydrogen on one molecule produces a negative charge, which is attracted to the positive charge formed by the loss of the hydroxy group from the other molecule.

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2 years ago
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<span>The disinfectant that was the most effective at controlling the growth of E. coli is disinfectant 2 because of the least number of Ecoli strains found on the dish compared to the other disinfectants. Also dish 4 that cointains water has the most number of Ecoli strains because water is not a disinfectant and Acoi do not die in water alone.</span>
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