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aivan3 [116]
2 years ago
8

For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather.

If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem. If one flight is selected at random from the airport in January, what is the probability that the flight selected will have at least one of the two types of delays?

Mathematics
1 answer:
lyudmila [28]2 years ago
8 0

Answer:

0.335

Step-by-step explanation:

1. There is a 30 percent chance of a flight being delayed because of icy weather ,then the probability of being delayed is 0.3 and of being not delayed is 0.7.

2. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem, then the probability of being delayed is 0.1 and the probabilty of not being delayed is 0.9.

3. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem (MP), then the probability of being delayed is 0.05 and the probabilty of not being delayed is 0.95. (See attached probability tree)

Delayed of icy weather - 0.3

Delayed of MP when weather is not icy - 0.7·0.05=0.035

Now, if one flight is selected at random from the airport in January, the probability that the flight selected will have at least one of the two types of delays is

0.3+0.035=0.335

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Step-by-step explanation:

a)

N(t) = 950e^0.0475t.

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The hypotenuse of a 45 -45° -90° triangle measures 18 cm. What is the length of one leg of the triangle?
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<h2>Steps</h2>

So the 45-45-90 triangle is considered to be a "special triangle" and has a rule with it. If the legs are x, then the hypotenuse is x√2. Since we know that the hypotenuse is 18, this means we can set up our equation as such:

x\sqrt{2} =18

From here we can solve for x. Firstly, divide both sides by √2.

x=\frac{18}{\sqrt{2}}

Next, we want to simplify this expression and to do that we first have to rationalize the denominator. With the right side, multiply the numerator and denominator by √2:

\frac{18}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}=\frac{18\sqrt{2}}{2}\\\\\\x=\frac{18\sqrt{2}}{2}

Next, divide:

x=9\sqrt{2}

<h2>Answer</h2>

<u>In short, the length of one leg of the triangle is 9√2 cm.</u>

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2 years ago
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Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10
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Answer:

<em>The probability is 42%</em>

Step-by-step explanation:

<u>Conditional Probability</u>

It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).

If P(A) is the probability of occurrence of A, P(A\cap B) is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:

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We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.

The probability that a randomly selected band member plays the trumpet is

\displaystyle P(A)=\frac{24}{125}

The probability that he or she has both attributes is

\displaystyle P(A\cap B)=\frac{10}{125}

Thus, the required conditional probability is

\displaystyle P(B|A)=\frac{\frac{10}{125}}{\frac{24}{125}}

\displaystyle P(B|A)=\frac{10}{24}=\frac{5}{12}=0.42

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Step-by-step explanation:

Let's consider each of these statements in view of the graph:

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Answer:

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Step-by-step explanation:

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Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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