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Mnenie [13.5K]
2 years ago
11

The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,

Mathematics
1 answer:
Andrej [43]2 years ago
7 0

Answer:

A. $18

B. $200

C. p\in (16,20)

Step-by-step explanation:

Function:

f(p) = -50p^2 + 1,800p - 16,000

<u>Parts A and B:</u>

The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

p_v=\dfrac{-b}{2a}=\dfrac{-1,800}{2\cdot (-50)}=\dfrac{1,800}{100}=18\\ \\f(p_v)=-50\cdot 18^2+1,800\cdot 18-16,000=200

The price that generates the maximum profit is $18

The maximum profit is $200

<u>Part C:</u>

The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all p\in (16,20), so the positive profit is for p\in (16,20)

In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.

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Help pls help plz help plz
ratelena [41]

Answer:

8

Step-by-step explanation:

(4+8)+6 = (6+4)+n

18 = 10+n

18-10 = n

n = 8

7 0
2 years ago
Would appreciate an explanation. PLEASE ANSWER THIS
Radda [10]

c^2 = a^2 + b^2 - 2*ab*Cos(C)

c = 16; a = 17; b = 8 (what you call a and b don't really matter. c does). Substitute.

16^2 = 17^2 + 8^2 - 2*17*8*Cos(C) Add the first 2 on the right.

256 = 289 + 64 - 282*cos(C)

256 = 353 - 282*cos(C) Whatever you do, don't do any more combing on the right side. Subtract 353 from both sides.

-97 = -282 * cos(C ) Divide by 282

0.34397 = cos(C)

cos-1(0.34397) = C ; C = 69.88 degrees.


Do you need more help on this question? All of these are done the same way.

8 0
2 years ago
Which of the following is not a solution for x &lt; 8?<br><br> x = 9<br> x = 7.95<br> x = 4.3
faltersainse [42]
The answer is 9 because If x has to be less than 8 then it can’t be 9
3 0
2 years ago
Read 2 more answers
Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa
WITCHER [35]
<span>65 = number of different arrangements of 2 and 3 card pages such that the total number of card slots equals 18. 416,154,290,872,320,000 = number of different ways of arranging 18 cards on the above 65 different arrangements of page sizes. ===== This is a rather badly worded question in that some assumptions aren't mentioned. The assumptions being: 1. The card's are not interchangeable. So number of possible permutations of the 18 cards is 18!. 2. That all of the pages must be filled. Since the least common multiple of 2 and 3 is 6, that means that 2 pages of 3 cards can only be interchanged with 3 pages of 2 cards. So with that said, we have the following configurations. 6x3 card pages. Only 1 possible configuration. 4x3 cards and 3x2 cards. These pages can be arranged in 7!/4!3! = 35 different ways. 2x3 cards and 6x2 cards. These pages can be arranged in 8!/2!6! = 28 ways 9x2 card pages. These can only be arranged in 1 way. So the total number of possible pages and the orders in which that they can be arranged is 1+35+28+1 = 65 possible combinations. Now for each of those 65 possible ways of placing 2 and 3 card pages such that the total number of card spaces is 18 has to be multiplied by the number of possible ways to arrange 18 cards which is 18! = 6402373705728000. So the total amount of arranging those cards is 6402373705728000 * 65 = 416,154,290,872,320,000</span>
6 0
2 years ago
I've been stuck on this for so long and I have an exam soon, anybody who can help me :'( ?
san4es73 [151]
(i)  speed = distance / time
so time =  distance / speed
here we have

time t = 1080/x  hours

(ii) return flight  time  = 1080 / (x + 30)  hours

(a)  1080/x - 1080/(x + 30) = 1/2

Multiplying  through by the LCD 2x(x + 30) we get:-

1080*2(x + 30) - 2x*1080 = x(x+30)
2160x + 64800 - 2160x = x^2 + 30x
x^2 + 30x - 64800  = 0

(b)  factoring;  -64800 = 270 * -240  ans 270-240 = 30 so we have

(x + 270)(x - 240) = 0   so x = 240  ( we ignore the negative -270)

So the speed for outward journey is 240 km/hr

(c) time ffor outward flight = 1080 / 240 =  4 1/2  hours

(d) average speed for whole flight = distance / time
   Time for outward journey = 4.5 hours and time for  return journey = d / v
= 1080 / (240+30) =  4 hours
 Therefore the average speed for whole journey =  2160 / 8.5 = 254.1 km/hr
8 0
2 years ago
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