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Free_Kalibri [48]

2 years ago

3

Shravan is ten years older than Gaurav’s age. Five years ago, one –seventh of shravan’s age was equal to one- fifth of Gaurav’s

age. Find their present ages.

1 answer:

svet-max [94.6K]2 years ago

7 0

Answer:

Shravan's age is 40 years old

Gaurav’s age is 30 years old

Step-by-step explanation:

Let

x-----> Shravan's age

y-----> Gaurav’s age

we know that

x=y+10 -----> equation A

(1/7)(x-5)=(1/5)(y-5) ----> equation B

substitute equation A in equation B and solve for y

(1/7)(y+10-5)=(1/5)(y-5)

(1/7)(y+5)=(1/5)(y-5)

5(y+5)=7(y-5)

5y+25=7y-35

7y-5y=25+35

2y=60

y=30 years

Find the value of x

x=y+10 ----> x=30+10=40 years

therefore

Shravan's age is 40 years old

Gaurav’s age is 30 years old

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Drew burned 1,800 calories Friday playing 1 hour of basketball and canoeing for 2 hours. On Saturday, he spent 2 hours playing b

V125BC [204]

Answer:

He burnt 1000 calories per hour when playing basketball.

Step-by-step explanation:

Let B be calories burned playing basketball, and C calories burned canoing.

1800 = B + 2C

3200 = 2B + 3C

From 1st equatipn, we get that B = 1800 - 2C

Replacing into the 2nd equation, we have:

3200 = 2(1800-2C) + 3C

3200 = 3600 - 4C + 3C

3200 = 3600 - 1C

C = 3600 - 3200

C = 400

Knowing C, we find B.

B = 1800 - 2C = 1800 - 2*400 = 1800 - 800 = 1000 calories.

6 0

2 years ago

Read 2 more answers

Nonamiya [84]

Your answer is E. $25.

First let under 12 = u, over 12 = o, and adults = a.
We can now write the equations:

2u + 3a + 3o = 174
4u + 2a = 122
a + o = 46

Because we know that a + o = 46, and 3a + 3o is in the first equation, we can multiply 46 by 3 to get what 3a + 3o equals. This makes 138.
Now we can substitute 138 into the first equation to get 2u + 138 = 174
2u = 36
u = 18

Now that we know what u equals, we can substitute it in to the second equation to get:
4(18) + 2a = 122
72 + 2a = 122
2a = 50
a = $25

I hope this helps! Let me know if you have any questions :)

8 0

2 years ago

16x^2-24x+7=0 equation and/or inequalities

Ivenika [448]

It is quadratic equation.
First we have find delta given by formula: delta= $b^{2}-4ac$
where our
a=16
b=-24
c=7
so, delta= $24^{2}-4*16*7=128$
Because delta is positive, there is real results.
Now we can use next formula x= $\frac{-b+ \sqrt{delta} }{2a}$
, to find roots (results, 2 results because its quadratic equation and delta is greater than 0)
x1= $\frac{24+ \sqrt{128} }{2*16} = \frac{3+ \sqrt{2} }{4}$
x2= $\frac{24- \sqrt{128} }{2*16} = \frac{3- \sqrt{2} }{4}$

5 0

2 years ago

Read 2 more answers

For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.

luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA) and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

$m\angle COB=arc\ CD$ ----> by central angle

we have

$arc\ CD=125^o$

therefore

$m\angle COB=125^o$

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

$m\angle BCA+m\angle\ ABC=90^o$ ---> by complementary angles in a right triangle

we have

$m\angle ABC=55^o$

substitute

$m\angle BCA+55^o=90^o$

$m\angle BCA=90^o-55^o=35^o\\$

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

$m\angle CBO+m\angle COB+m\angle BCO=180^o$ ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

$m\angle COB=125^o$

$m\angle BCO=m\angle BCA=35^o$ -----> have measure equal to 35 degrees

substitute

$m\angle CBO+125^o+35^o=180^o$

$m\angle CBO=180^o-160^o=20^o$

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

$m\angle ABC=m\angle CBO+m\angle ABO$ ----> by angle addition postulate

we have

$m\angle ABC=55^o$

$m\angle CBO=20^o$

substitute

$55^o=20^o+m\angle ABO$

$m\angle ABO=55^o-20^o=35^o$ ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

3 0

2 years ago

Elise does not like sorbet, so she omits that ingredient and adds 5 percent of each of the other ingredients. How many cups of p

Arisa [49]

Answer:

20 cups of punch

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If Elise adds 5 percent of each of the other ingredients

then

the new percentages are

Ginger Ale=40%+5%=45%

Orange Juice=25%+5%=30%

Pineapple Juice=20%+5%=25%

Sorbet=0%

Find out how many cups of punch will she have if she uses 6 cups of orange juice, using proportion

Let

x ----> the total cups of punch

$\frac{6}{30\%}=\frac{x}{100\%}\\\\x=6(100)/30\\\\x=20\ cups\ of\ punch$

6 0

2 years ago