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MrRa [10]
2 years ago
14

Calculate cos 0 to two decimal places

Mathematics
2 answers:
pashok25 [27]2 years ago
7 0

For this case we have by definition of the Cosines Law that:

7 ^ 2 = 10 ^ 2 + 8 ^ 2-2 (10) (8)* cosΘ

49 = 100 + 64-160cosΘ

49 = 164-160cosΘ

49-164 = -160cosΘ

-115 = -160cosΘ

115 = 160cosΘ

cosΘ= \frac {115} {160} = 0.71875

Rounding off we have, 0.72

ANswer:

Option C

Sergio [31]2 years ago
3 0

We can use the law of cosines as follows:

7^2 = 8^2+10^2-2\cdot 8 \cdot 10 \cdot \cos(\theta)

We can rewrite this equation as

49 = 164-160 \cdot \cos(\theta) \iff 160 \cdot \cos(\theta) = 115 \iff \cos(\theta)=\dfrac{115}{160}\approx 0.72

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First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

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As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

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Second Question

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Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

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This gives a to be:

a\approx28.44

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Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





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