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topjm [15]
2 years ago
15

In the diagram below, O is circumscribed about quadrilateral ABCD. what is the value of x?​

Mathematics
2 answers:
cestrela7 [59]2 years ago
7 0

Answer:

104

Step-by-step explanation:

cuz it iz

netineya [11]2 years ago
6 0

Answer:

(D)x=104^{\circ}

Step-by-step explanation:

Given: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

To find: the value of x.

Solution: It is given that circle O is circumscribed about quadrilateral ABCD such that ∠ABC=91° and ∠ADC=x-15°.

We know that the sum of opposite angles of the cyclic quadrilateral is 180°, therefore

{\angle}ABC+{\angle}ADC=180^{\circ}

Substituting the given values, we have

91^{\circ}+x-15^{\circ}=180^{\circ}

x+76^{\circ}=180^{\circ}

x=104^{\circ}

thus, the value of x is 104^{\circ}.

Hence, option D is correct.

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M∠AFD=90°. m∠AFB=31°. Find m∠CFEm.
Setler [38]
AFB = CFD = 31
BFC = 90 - (31+31) = 28
DFE = BFC = 28
CFE = CFD + DFE = 31 + 28 = 59
7 0
2 years ago
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Weiming, Farhan and Sam had some comic books.
mixas84 [53]

Answer:

Farhan had 9 comic books

Sam had 51 comic books and lived in his Mother's basement

Step-by-step explanation:

W + F = 36

W = 3F

3F + F = 36

F = 9

W = 27

S + F = 60

S + 9 = 60

S = 51

5 0
1 year ago
Paula weighed 65.5 kilograms before she started training she as lost 3500grams how much does she weigh
Alborosie
Hello!

We have the following data:

Paula weight (before training) = 65.5 kg
Weight lost by Paula (in training) = 3500 grams = 3.5 kg
Paula's weight (after training) =?

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5 0
2 years ago
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Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56
kogti [31]

Answer:

24.2(to the nearest tenth)

Step-by-step explanation:

The question is ungrouped data type

standard deviation =√ [∑ (x-μ)² / n]

mean (μ)=∑x/n

           = \frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}

          =33.3

x-μ   for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49

∑ (x-μ)² will be = 7028.59

standard deviation = √(7028.59 / 12)

                      =24.2

     

6 0
2 years ago
What is 4 square root of 81 to the fifth power in exponential form
creativ13 [48]

Answer:

B is the answer.

Step-by-step explanation:

x^{\frac{m}{n} }  = \sqrt[n]{x^{m} }  

\sqrt[4]{81^{5} } =  81^{\frac{5}{4} }

5 0
2 years ago
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