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nadezda [96]
2 years ago
9

Guest must be at least 42 1/2 inches tall to go on an amusement park ride. Which inequality represents the heights of the guest

allowed on the ride.
Mathematics
2 answers:
sweet-ann [11.9K]2 years ago
8 0
X > 42.5 or = 42.5 
The guest must be greater than or equal to 42.5 inches. 
Lubov Fominskaja [6]2 years ago
8 0

Answer:

Step-by-step explanation:

You might be interested in
Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

3 0
2 years ago
Rammy has $9.60 to spend on some peaches and a gallon of milk. Peaches
sergeinik [125]

Answer:

\large \boxed{\text{5.00 lb}}

Step-by-step explanation:

\begin{array}{rcl}1.20x + 3.60 & \leq & 9.60\\1.20x & \leq & 6.00\\x &\leq & \mathbf{5.00}\\\end{array}\\\text{Rammy can buy $\large \boxed{\textbf{5.00 lb}}$ of peaches.}

Check:

\begin{array}{rcl}1.20(5.00) + 3.60 & \leq & 9.60\\6.00 + 3.60 & \leq & 9.60\\9.60 & \leq & 9.60\\\end{array}

OK.

5 0
2 years ago
What would you do if when you okay so he said yes would go?
Debora [2.8K]
I'm confused but no? lol
6 0
2 years ago
A recipe for 11 pizza crust calls for 3838 tablespoon of salt. How much salt is needed to make 33 pizza crusts?
max2010maxim [7]
Its 11,514 tablespoons of salt
8 0
2 years ago
What is the numerator of the simplified sum? StartFraction x Over x squared + 3 x + 2 EndFraction + StartFraction 3 Over x + 1 E
ozzi

Answer:

4x + 6

Step-by-step explanation:

Given

\frac{x}{x^2+3x+2} + \frac{3}{x+1}

Before we can add the fractions we require them to have a common denominator.

Factor the denominator of the first fraction

\frac{x}{(x+1)(x+2)} + \frac{3}{x+1}

Multiply the numerator / denominator of the second fraction by (x + 2)

= \frac{x}{(x+1)(x+2)} + \frac{3(x+2)}{(x+1)(x+2)} ← fractions now have a common denominator

Add the numerators leaving the denominators

= \frac{x+3(x+2)}{(x+1)(x+2)}

= \frac{x+3x+6}{(x+1)(x+2)}

= \frac{4x+6}{(x+1)(x+2)} ← simplified sum with numerator 4x + 6

7 0
2 years ago
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