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WITCHER [35]
2 years ago
3

The function f(x) = –12x + 144,000 is used to model the number of granola bars in stock depending on the number of boxes, x, one

machine packages if the machine starts with 144,000 granola bars. The mathematical range for the function is the set of real numbers.
Which statement describes the limitation for the reasonable range compared to the mathematical range?

The reasonable range is limited to the whole numbers when 0 ≤ y ≤ 12,000.
The reasonable range is limited to the rational numbers when 0 ≤ y ≤ 12,000.
The reasonable range is limited to the whole numbers when 0 ≤ y ≤ 144,000.
The reasonable range is limited to the rational numbers when 0 ≤ y ≤ 144,000.
Mathematics
1 answer:
allsm [11]2 years ago
8 0

Answer:

The reasonable range is limited to the whole numbers when 0 ≤ y ≤ 144,000.

Step-by-step explanation:

Notice that even though the range of the function is mathematically defined for all real numbers, in the real world you can't have more than 144,000 granola bars; that occurs when you have no boxes, or in other words, when x = 0

On the other hand, in the real word you can't have a negative quantity of a thing (you can't have minus 2 popsicles, for example). Given that granola bars are things, you must have at least 0 granola bars; in other words the quantity of granola bars must be greater or equal zero.

We know that in the real word you cant have more than 144,000 granola bars, and you must have at least 0 granola bars; therefore, the reasonable range of the function f(x) = –12x + 144,000 is 0 ≤ y ≤ 144,000.

Since we are talking of full granola bars here, the range is limited to whole numbers (whole granola bars).

We can conclude that the correct answer is: The reasonable range is limited to the whole numbers when 0 ≤ y ≤ 144,000.

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Find the value of sin100.sin120.sin140.sin160​
NARA [144]

The value of sin100.sin120.sin140.sin160 is 0.1875

Step-by-step explanation:

To find the value of sin100.sin120.sin140.sin160, let us find the value of each angle.

The value of sin100=0.9848

The value of sin120=\frac{\sqrt{3} }{2}

The value of sin140=0.6428

The value of sin160=0.3420

Substituting the values of sin, we get,

sin100.sin120.sin140.sin160=0.9848*\frac{\sqrt{3} }{2} *0.6428*0.3420

Multiplying the values of sin, we get,

sin100.sin120.sin140.sin160=0.1875

Thus, the value of sin100.sin120.sin140.sin160 is 0.1875

8 0
2 years ago
8% of the employees at a shop work part time. If there are 4 part time employees at the shop, how many employees are there in to
Murljashka [212]

Answer:

50 employees

Step-by-step explanation:

We can set up a proportion which would be

4/x = 8/100

This shows 4 out of x people is the same as 8% of 100.

We divide 100 by 8, and then multiply by 4 to get 50.

We can check this by plugging 50 into the proportion.

4/50 = 0.08

8/100= 0.08

There are 50 total employees at the shop.

4 0
2 years ago
Expand (3 - 2x)6. What is the coefficient of the sixth term?
stich3 [128]
To expand (3 - 2x)^6 use the binomial theorem:

(x + y)^ n = C(n,0) x^ny^0 + C(n,1)x^(n-1) y + C(n,2)x^(n-2) y^2 + ...+ C(n,n+1)xy^(n-1) + C(n,n)x^0y^n


So, for x = 3, y = -2x , and n = 6 you get:

(3 - 2x) ^6 = C(6,0)(3)^6 + C(6,1)(3)^5 (-2x) + C(6,2) (3)^4 (-2x)^3 + C(6,3) (3^3) (-2x)^4 + C(6,4)(3)^2 (-2x)^4 + C(6,5) (3) (-2x)^5 + C(6,6) (-2x)^6

So, the sixth term is C(6,5)(3)(-2x)^5 =  6! / [5! (6-5)! ] * 3 * (-2)^5 x^5 = - 6*3*32 = - 576 x^5.

The coefficient of that term is - 576.

Answer: - 576
5 0
2 years ago
Jace has consumed 1,500 calories so far today. He has also burned off 400 calories at the gym. He would like to keep his daily c
maksim [4K]

Answer:

C

Step-by-step explanation:

Consumed = 1500

Burned = 400

Calorie Count total = 1500 - 400 = 1100

His target is 1900, so he will need 1900 - 1100 = 800 calories to consume more

So, 1100 is NOT a viable solution because he will go over 1900 if that happens. Hence, C is the correct choice.

7 0
2 years ago
Read 2 more answers
For the following indefinite integral, find the full power series centered at t=0 and then give the first 5 nonzero terms of the
Natali [406]

Answer:

The open interval of convergence is 1

Step-by-step explanation:

The detailed explanation is given in the attached document.

5 0
2 years ago
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