Answer:
Option (D) is the correct answer of this question.
Explanation:
Moore's Law relates to Moore's theory that the number of transistors on a microchip doubles every two years while device costs are halved.
Interpretations of Moore's law assert the computing power doubles every 18 months.The Moore's Law theory states that development is exponential.Moore's Law states that every couple of years we should expect our computers to increase their speed and capacity and we'll pay less for them.h
Option(A),Option(B) ,Option(c) and option(E) do not belongs to Moore's law so these options are incorrect options.
Answer:
The answer to this question can be given as:
Statement:
number = int(line.strip())
Explanation:
In the above statement, we declare an integer variable number accept the integer value from the file that name is line. In this line, we use the strip() function. This function returns a duplicate string with both starting and tracking characters removed (based on the string parameter passed). The strip() function removes characters from both sides (left and right) based on the parameter(a string defining the collection of characters to be removed).
<span>A touch screen gives response and acts simply with a touch on the screen area. Reflective screen is not a basic type of touch screen. The reflection can be reduced for the touch screen when it is combined with the LCD and the screen still be very visible. These screens can be anti glare and safe to the eyes.</span>
In java...
public boolean checkSquare(int n){
int actualNumber = n;
int squareRoot = (int)Math.sqrt(n);
int squaredNumber = Math.pow(squareRoot,2);
if(squaredNumber==actualNumber){
return true;
} else {
return false;
}
}
Answer:
C++.
Explanation:
<em>Code snippet.</em>
#include <map>
#include <iterator>
cin<<N;
cout<<endl;
/////////////////////////////////////////////////
map<string, string> contacts;
string name, number;
for (int i = 0; i < N; i++) {
cin<<name;
cin<<number;
cout<<endl;
contacts.insert(pair<string, string> (name, number));
}
/////////////////////////////////////////////////////////////////////
map<string, string>::iterator it = contacts.begin();
while (it != contacts.end()) {
name= it->first;
number = it->second;
cout<<word<<" : "<< count<<endl;
it++;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////
I have used a C++ data structure or collection called Maps for the solution to the question.
Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.
