Circumcenter and circumcirle are shown in the attachment. Assume that the triangle is DEF instead of ABC and that the intersection of perpendiculars is H.
The definition of the circumcenter of a triangle is defined as the point of intersection of all the perpendicular bisectors in the triangle.
The circumcircle passes by all three of the triangle's vertices.
Based on the above, the right choiceS will be:
Point H is the center of the circle that passes through points D, E, and F.
HD = HE
(a) 4
(b) y = sqrt(9 - (9/16)x^2)
The best guess to the formula using knowledge of the general formula for an ellipse is:
x^2/16 + y^2/9 = 1
(a). An ellipse is reflectively symmetrical across both the major and minor axis. So if you can get the area of the ellipse in a quadrant, then multiplying that area by 4 would give the total area of the ellipse. So the factor of 4 is correct.
(b). The general equation for an ellipse is not suitable for a general function since it returns 2 y values for every x value. But if we restrict ourselves to just the positive value of a square root, that problem is easy to solve. So let's do so:
x^2/16 + y^2/9 = 1
x^2/16 + y^2/9 - 1 = 0
x^2/16 - 1 = - y^2/9
-(9/16)x^2 + 9 = y^2
9 - (9/16)x^2 = y^2
sqrt(9 - (9/16)x^2) = y
y = sqrt(9 - (9/16)x^2)
The answers are-
XP=YP for an acute triangle
YP=ZP for an obtuse triangle
XP=YP For an obtuse triangle
Answer:
20
Step-by-step explanation: