Tricia should take the money that she already has saved no matter how little it is and split it evenly between savings and emergency needs
        
                    
             
        
        
        
Answer:
Option (D)
Step-by-step explanation:
Given polynomial is, 
2x³ - 3x² - 3x + 2
If (x - 2) is the factor of the given polynomial,
By synthetic division we can get the other factor.
2 |  2     -3       -3       2    
   
     <u>         4         2      -2          </u>
      2      1         -1        0
Therefore, other factor of the given polynomial is (2x² + x - 1) 
Now (2x² + x - 1) = 2x² + 2x - x - 1 
                            = 2x(x + 1) -1(x + 1)
                            = (2x - 1)(x + 1) 
Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)
Option (D) will be the answer.
 
        
             
        
        
        
As a navigator of this ship, you must consider the measure of the arc. Using the distance between the two lighthouses and the arc measurement, you can find the radius and center of the circle to set a reasonable distance in keeping the ship in safe waters.
        
             
        
        
        
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75  [ probability that Nathan is allergic ]
P(T|A)=0.98  [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A) 
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A) 
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
        
             
        
        
        
Given :  tan 235 = 2 tan 20 + tan 215
To Find : prove that
Solution:
tan 235 = 2 tan 20 + tan 215
Tan x = Tan (180 + x)
tan 235 = tan ( 180 + 55) = tan55
tan 215 = tan (180 + 35) = tan 35
=> tan 55 = 2tan 20 + tan 35
55 = 20 + 35
=> 20  = 55 - 35
taking Tan both sides
=> Tan 20 = Tan ( 55 - 35)
=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)
Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1
=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)
=> Tan 20  = (Tan 55 - Tan 35) /2
=> 2 Tan 20  = Tan 55 - Tan 35
=> 2 Tan 20 +  Tan 35 = Tan 55
=>  tan 55 = 2tan 20 + tan 35
=>  tan 235 = 2tan 20 + tan 215
QED
Hence Proved