In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.
For only one person, we use P(1), same reasoning should hold for other subscripts.
P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841
Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
Answer:
Step-by-step explanation:
1) To find the cube root of a number prime factorize
46656 = 2*2*2*2*2*2 * 3 * 3 * 3 * 3 * 3 * 3
![\sqrt[3]{46656}=\sqrt[3]{2*2*2*2*2*2*3*3*3*3*3*3} =2*2*3*3 = 36](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B46656%7D%3D%5Csqrt%5B3%5D%7B2%2A2%2A2%2A2%2A2%2A2%2A3%2A3%2A3%2A3%2A3%2A3%7D%20%20%3D2%2A2%2A3%2A3%20%3D%2036)
Length of each side = 36 m
Q) i) -512 = (-8) * (-8)*(-8)
-512 is a cube number
v) -17576 = (-26) * (-26)*(-26)
-17576 is cube number
Answer:
<u>12.5% ≈ 13%</u>
Step-by-step explanation:
The rest of the question is: There are 75 pills in the batch.
The current batch of pills is the first of the day and our goal is to produce a total of 600.
If there are 75 pills in the batch so percentage of goal completed will be
[(number of pills in the batch)/(Total pills)] * 100

≈ 13% to the nearest whole number
2,070mg 86%
— = —
? mg 100%
Cross multiply (2,070 X 100) which equals 207,000
Then divide 207,000 by 86 which equals
2,406.976
Then you round so you get 2,407
The Answer is 2,407 milligrams