Prove:
The angle inscribed in a semicircle is a right angle.
The inscribed angle theorem states that the angle θ, inscribed in a circle is half the measure of the central angle of the circle. So, if the given is a semi-circle, then the inscribed angle is half of 180, therefore, 90 degrees and a right angle. <span />

- 128 cellphones were sold in a week
- 37 more cellphones more were sold than the week before
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- 293 cellphones were sold in given 2 weeks
we know that
The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.
so
<u>Find the measure of the angle LAM</u>
m∠LAM is equal to
![\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2A%5Barc%5C%20KJ%2Barc%5C%20LM%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%5B170%2B80%5D%5C%5C%5C%5C%3D125%5C%20degrees)
<u>Find the measure of the angle MAJ</u>
we know that
m∠LAM+m∠MAJ=
° ------> by supplementary angles
m∠MAJ=
m∠MAJ=
°
therefore
<u>the answer is</u>
The measure of the angle MAJ is 
we have

we know that
<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.
So
in this problem
the constant term is equal to 
and the first monomial is equal to
-----> coefficient is 
So
possible values of p are 
possible values of q are 
therefore
<u>the answer is</u>
The all potential rational roots of f(x) are
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