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Orlov [11]
2 years ago
11

You are told that in a sample of size 225 the mean is 48.5 and the standard deviation is 1.8. The study is reported with 90% con

fidence level. Explain how to determine if 48.8 is within the confidence interval.
CL(%); 90, 95, 99
z*score:1.645, 1.96, 2.58
Mathematics
2 answers:
gregori [183]2 years ago
4 0
<span>To find the margin of error, multiply the z-score by the standard deviation, then divide by the square root of the sample size.</span><span>The z*-score for a 90% confidence level is 1.645.</span>The margin of error is 0.20.The confidence interval is 48.3 to 48.7.48.8 is not within the confidence interval. 

natali 33 [55]2 years ago
3 0
<span>To find the margin of error, multiply the z-score by the standard deviation, then divide by the square root of the sample size.

</span><span>The z*-score for a 90% confidence level is 1.645.</span>The margin of error is 0.20.

The confidence interval is 48.3 to 48.7.

48.8 is not within the confidence interval.

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What are the differences among an experiment, a study, and a survey? Complete the explanation of the differences by selecting th
artcher [175]

Answer:

The full question is

<em>What are the differences among an experiment, a study, and a survey? </em>

<em> </em>

<em>1. In an observational study, randomization of subjects ______ </em>

<em>A. occurs </em>

<em>B. does not occur </em>

We understand randomization as a random process of assigning experimental subjects to treatment groups. Through this process, we have more control about variables which are not related to the experiment.

In an observational study, the researcher doesn't change anything, he or she studies the events as they are, without using any randomization process.

Therefore, the right answer here is B.<em> </em>

<em />

<em>2. A survey _______ </em>

<em>A. poses no interference on subjects </em>

<em>B. makes inferences about a population </em>

<em> </em>A survey poses no interference on subjects, actually if it does, then that survey is not reliable. An important charactersitic of a survey is that it must be objective, that way it will be reliable enough to use it in the research.

Therefore, the right answer is A.

<em />

<em>3. In an experiment, ___________ to discern differences in a response variable. </em>

<em>A. treatment is imposed </em>

<em>B. inferences are made </em>

<em>C. randomization does not occur</em>

Experiments are characterized by having certain "stimulus" at least in one group of subjects, that way researches compare data sets to prove their hypothesis.

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8 0
2 years ago
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a stand
julsineya [31]

Answer:

There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

Also, a probability is unusual if it is lesser than 5%. If it is unusual, it is surprising.

In this problem:

The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a standard deviation of 3 minutes, so \mu = 7, \sigma = 3.

We need to find the probability that it takes less than one minute to find a parking space.

So we need to find the pvalue of Z when X = 1

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - 7}{3}

Z = -2

Z = -2 has a pvalue of 0.0228.

There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.

5 0
2 years ago
A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

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There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0
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The answer is C. 1

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5 0
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