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olga nikolaevna [1]

2 years ago

7

Nancy was laid off and applied for unemployment benefits in July. In her state, the weekly unemployment benefit is 55% of the 2

6-week average of the two highest salaried quarters of the year leading to her application. In April, May, and June, Nancy earned a total of 13,500. In January, Febuary, and March her total income was 12,775. What will Nancy weekly benfits be?

1 answer:

tankabanditka [31]2 years ago

8 0

Answer:

$277.91

Step-by-step explanation:

"The 26-week average of the two highest salaried quarters of the year leading to her application" would be the average of $13,500 and $12,775, or

$13,500 + $12,775

---------------------------- = $13137.50

2

Dividing this by 26 weeks (equivalent to 6 months), we get $505.29.

Nancy's weekly employment benefit would be 55% of that, or $277.91.

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2 years ago

In a GP if T3 = 18 and T6 = 486 Find:- T10

mote1985 [20]

Answer:

The 10th term of the G.P is 29.

Step-by-step explanation:

Given : In a GP if $T_3=18$ and $T_6 = 486$ .

To find : The term $T_{10}$ ?

Solution :

The geometric sequence is in the form, $a,ar,ar^2,ar^3,...$

Where, a is the first term and r is the common ratio.

The nth term of G.P is $T_n=ar^{n-1}$

We have given, $T_3=18$

i.e. $T_3=ar^{3-1}$

$18=ar^{2}$ ....(1)

$T_6 = 486$

i.e. $a_6=ar^{6-1}$

$486=ar^{5}$ ....(2)

Solving (1) and (2) by dividing them,

$\frac{486}{18}=\frac{ar^{5}}{ar^{2}}$

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$r=\sqrt[3]{27}$

$r=3$

Substitute in (1),

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The first term is a=2 and the common ratio is r=3.

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$T_{10}=2+27$

$T_{10}=29$

Therefore, The 10th term of the G.P is 29.

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2 years ago

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A middle school took all of its 6th grade students on a field trip to see a symphony. The students filled 855 seats, which was 4

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Answer:

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