The probability of a dart (thrown at random) landing in the area marked F is:
1/16
<h2>Step-by-step explanation:</h2>We know that the probability of an outcome is defined as the chance of occurrence of an outcome and it is calculated as the ratio of number of favorable outcomes to the total number of outcomes.
We first make equal sections i.e. we divide the figure into equal sections and observe that:
A and D is made up of 4 sections.
B,C and E is made up of 2 sections.
F and G are made up of 1 section.
This means that the total number of sections are: 4+4+2+2+2+1+1=16
Hence,
Probability(landing on F)=1/16
( Since there are total 16 sections and F is made up of 1 )
Answer:
a = -3.8
b = -2.6
c = 1.7
d = 4.4
e = 1.0
Step-by-step explanation:
In the figure attached, the tables are shown.
In an inverse relationship, any point (x,y) in one table is transformed to (y,x) in the other one. For example, in Table A coordinate (1, 2) is present, then in Table B (the inverse), coordinate (2, 1) must be present.
Answer:
The graph that includes points (-3,-3) and (0,3)
Step-by-step explanation:
In the pictures attached, the options are shown.
The equation:
y+3=2(x+3)
has the point-slope form, which is:
y-y₁=m(x-x₁)
where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:
y+3=2(0+3)
y+3 = 6
y = 6 - 3
y = 3
Then, point (0, 3) is on the line.
