You did not include the diagram, but the answer is very easy to figure out. The mRNA base that will go in location 1 depends on the DNA base in location 1:
If the DNA base is Adenine (A), the mRNA base will be Uracil (U)
If the DNA base is Thymine (T), the mRNA base will be Adenine (A)
If the DNA base is Cytosine (C), the mRNA base will be Guanine (G)
If the DNA base is Guanine in (G), the mRNA base will be Cytosine (C)
Answer: It should be <u>C</u>.
Explanation:
For separate ecosystems to be classified as the same type of biome, they must —
x have deciduous forests
.
x be located along the equator
.
√ have similar organisms and climates
.
x be at least one hundred square meters in area.
Answer:
Energy is used up while running, and cellular respiration needs oxygen to produce more energy. Energy is used up while running, and cellular respiration needs carbon dioxide to produce more energy.
Explanation:
Answer:
The sample a which is solid at 20°C is "Iodine"
The sample b which is liquid at 20°C is "Bromine"
The sample c which is gas at 20°C is "Chlorine"
Explanation:
Iodine : It starts melting at 113.7°C, so the solid sample found is the iodine. Iodine is present in both solid as well as in vapor state. Basically it is kept in closed jars. Only when it reaches the temperature above the melting point is starts melting.
Bromine: It is a non metallic element that is present in the liquid state, being a member of halogen group. It is heavy, mobile and dangerous reddish brown liquid. It is corrosive in nature, when comes in contact with human tissue and causes irritation in eye when comes in contact with its vapor.
Chlorine: In room temperature it is gas, as it has weak intermolecular interaction which fails to keep the molecules closely attached.
Answer:
The answer is XX.
Explanation:
Let us say that X is the dominant gene and x is the recessive gene for the height of the pea plants. Pea plants need to be homozygous or heterozygous to have the short phenotype which means it needs to have the genotype xx or Xx.
The F2 offspring has a ratio of 74,5% tall plants and 25,5% short plants. For these results, the stem height pea plant needs to be homozygous which is an XX genotype for the tall pea plant.
I hope this answer helps.
