Answer:
5'GATCGTAA3'
5'ATTCTAGA3'
Explanation:
As requested in the question above, the primers were presented with 8 nucleotides, with the nitrogenous bases of the DNA, and in the 5'-3 'direction.
Primers are small fragments of DNA that are used by DNA polymerase to form new strands. The primes attach to pieces on the ribbon, through the complementarity of the nitrogenous bases, serving as a template for the DNA polymerase to create the new ribbon.
DNA polymerase uses primers at the origin of replication, and can follow the path from the right or from the left, depending on the primers used, for this reason, this question has two answers.
The correct answer is (C) biomass at each trophic level
Pyramid of energy is a graphic representation of amount of energy trapped per unit time and area in different trophic levels of a food chain with producers forming the base and top carnivores the tip. As the biomass of producers are always greater than the carnivores, the pyramid of energy can't be inverted.
The individual organisms that frame a population are additional or less equally spaced, spread every which way with no predictable pattern, or clustered in teams. These are called the uniform, random, and clumped dispersion patterns. Uniform refers to the evenly distributed population, random means random spacing and clumped shows the distribution in clusters.
Food supply and resources are directly proportional to a particular distribution pattern. Random distribution occurs when several pollen grains of some flowers were carried by wind or bees. These flowers will then bloom where they were scattered.
hope this um ... helps hehe ........
Answer:
p = 0.34
Explanation:
The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.
If 44 organisms are green, that means 44 are qq.
For genotype frequencies, the equation is:
homozygous dominant genotype + heterozygous + homozygous recessive = 100%
Which is denoted as
p² + 2pq + q² = 1
We know that q² = 44/100 = 0.44
To work out q, we can do 
= 0.66
For allele frequencies, the total must add up to 100%, so
p + q =1
We know that q= 0.66
So p = 0.34, because 0.66 + 0.34 = 1
Answer:
Following are the correctly rank steps:
1. The binding of glucose takes place with the transporter on one side of the membrane.
2. The binding of glucose leads to a conformational change, which opens the site of binding on the contrary side of the membrane.
3. The dissociation of glucose takes place.
4. The transporter moves back to the beginning conformation.
