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MaRussiya [10]
2 years ago
13

The amount of time (t) in minutes it takes Jeff to mow an average sized yard is related to (n) the number of yards he mows. The

equation is t = 2n + 12. How many lawns does Jeff mow if it takes him 30 minutes?
Mathematics
1 answer:
Sveta_85 [38]2 years ago
4 0

Answer:

Jeff mows 9 yards of lawn in 30 minutes

Step-by-step explanation:

The equation that models the amount of time (t) in minutes it takes Jeff to mow an average sized yard is t=2n+12, where n is the number of yards he mows.

To find the number of yards Jeff mows in 30 minutes, we set the equation to 30 and solve for n.

\implies 2n+12=30

Add -12 to both sides:

\implies 2n=30-12

\implies 2n=18

Divide both sides by 2

\implies \frac{2n}{2}=\frac{18}{2}

\implies n=9

Hence Jeff mows 9 yards of lawn in 30 minutes.

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There were 567 people at a concert when a band started playing. After each song, only one-third of the people stayed to hear the
Solnce55 [7]
To write the function correctly, it is important to assign variables correctly and understand the situation of the problem clearly. For this, we let y the number of people and x as the number of songs played.

At x = 0   y = 567
at x = 1   y = 567 - 567(1/3)
at x = 2   y = 567 - 567(1/3)(1/3)
at x = 3   y = 567 - 567(1/3)(1/3)(1/3)

Therefore, the number of people left after x songs would be represented by the equation:

y = 567 - 567(1/3)x
y = 567 ( 1- x/3 )
7 0
2 years ago
Read 2 more answers
Mrs.Steffen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin
qaws [65]

Answer:

a. \\ 10! = 3628800;

b. \\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}

Step-by-step explanation:

We need here to apply the <em>Multiplication Principle </em>or the <em>Fundamental Principle of Counting</em> for each answer. Answer <em>b</em> needs an extra reasoning for being completed.

The <em>Multiplication Principle</em> states that if there are <em>n</em> ways of doing something and <em>m</em> ways of doing another thing, then there are <em>n</em> x <em>m</em> ways of doing both (<em>Rule of product</em> (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are <em>ten</em> students. When one is selected, there is no other way to select it again. So, <em>no repetition</em> is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is <em>why</em> the <em>Multiplication Principle</em> is important here.

This could be expressed mathematically using n!:

\\ n! = n * (n-1)! * (n-2)! *...* 2*1.

For instance, \\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.

So, for the case in question, the <em>ten</em> students can line up in:

\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800 ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy <em>only</em> the following places in forming the file:

\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th} <em>places</em>.

The members of Group 2 <em>only</em>:

\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th} <em>places</em>.

And the members of Group 3, the following <em>only</em> ones:

\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th} <em>places.</em>

Well, having into account these possible places for each member of G1, G2 and G3, there are: <em>10! ways</em> for lining up members of G1; <em>10! ways</em> for lining up members of G2 and, also, <em>10! ways</em> for lining up members of G3.

After using the <em>Multiplication Principle</em>, we have, thus:

\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19} <em>ways the students can line up to come in from recess</em>.

3 0
2 years ago
If week 1=5, week 2=3, week 3=7, week 4=5 what will week 5 be?
olga2289 [7]

Answer: 11

Step-by-step explanation:

The sequence goes +4, +1, +5, +1... so obviously the next number will be +6. So, 5+6=11

The answer is week 5=11

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The Zonda Information and Telephone Company (ZI&amp;T) calculates a customer’s total monthly cell phone
Olenka [21]

Answer:

The answer of the following question is m = \frac{C - b - bt}{r + rt}.

Solution:

C = (b + rm)(1 + t),

C = b + rm + bt + rmt

C = b + bt + rm + rmt

C - b - bt = m (r + rt)

\frac{C - b - bt}{r + rt} = m

t\neq -1,  

r\neq 0

6 0
2 years ago
Which of the following statements is true? A) A counting semaphore can never be used as a binary semaphore. B) A binary semaphor
saveliy_v [14]

Answer:

C

Step-by-step explanation:

Statement C of the following statements is true

C). Spin-locks can be used to prevent busy waiting in the implementation of semaphore.

5 0
2 years ago
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