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2 years ago

In ΔBCA, CA = 15 cm, CF = 7 cm, BH = 3 cm. Find the perimeter of ΔBCA.

Mathematics

2 answers:

evablogger [386]2 years ago

7 0

Answer:

The perimeter of the triangle is equal to 36 cm

Step-by-step explanation:

we know that

The inscribed circle contained in the triangle BCA is tangent to the three sides

we have that

BF=BH

CF=CG

AH=AG

step 1

Find CG

we know that

CF=CG

CF=7 cm

therefore

CG=7 cm

step 2

Find AG

we know that

CA=AG+CG

we have

CA=15 cm

CG=7 cm

substitute

15=AG+7

AG=15-7=8 cm

step 3

Find AH

Remember that

AG=AH

we have

AG=8 cm

therefore

AH=8 cm

step 4

Find BF

Remember that

BF=BH

BH=3 cm

therefore

BF=3 cm

step 5

Find the perimeter of the triangle

P=AH+BH+BF+CF+CG+AG

substitute the values

P=8+3+3+7+7+8=36 cm

Sphinxa [80]2 years ago

5 0

Answer:

The answer is 36

Step-by-step explanation:

I took the test.... aka you're welcome :)

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Step-by-step explanation:

step 1

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see the attached figure to better understand the problem

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