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2 years ago

. Write a statement that throws an IllgalArgumentException with the error message Argument cannot be negative.

Computers and Technology

1 answer:

dybincka [34]2 years ago

8 0

Answer:

public class PostAccount

{

public void withdraw(float savings)

{

if (savings >=0 )

{

IllegalArgumentException exception

= new IllegalArgumentException("Savings cannot be negative");

throw exception;

}

balance = savings - withdraw;

}

Explanation:

IllgalArgumentException is a type of NumberFormatException of runtime exception. Here in the program we have created an object of IllgalArgumentException class and after that we have thrown the error to show the condition if it does not satisfy the if condition.

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You have been employed as a technical consultant to a computer shop chain. You are given the task of creating a short consumer b

brilliants [131]

Answer:

The five factors to consider when trying to choose between a Solid State Drive, a Hard Disk Drive and, an External Hard Disk Drive are:

Read/Write Speed
Weight
Power Consumption
Cost
Storage Capacity

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Cheers!

3 0

2 years ago

List at least six things you would check for if you were asked to evaluate the workspace of an employee for ergonomics

Evgen [1.6K]

Assessing the risk that surrounds stationary work of employees spending hours at their stations is essential. Below is a list of fundamental ergonomic principles that help identify ergonomic risk factors.

1. Are the employees maintained in a neutral posture?

2. Does the stationery allow for movement and stretching?

3. Is there adequate lighting?

4. Are chairs adequately adjustable?

5. Are there appropriate foot rest?

6. Is there extra storage for better desk organization?

0 0

2 years ago

Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*

natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3() d, e, f

fun2() c, d, e

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "c" of fun2() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3() d, e, f

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "b, c" of fun1() will be visible

variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1() b, c, d

fun3() d, e, f

fun2() c, d, e

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun1().

In fun1(), the local variables "b, c, d" of fun1() will be visible

variable "e, f" of fun3() will be visible

variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2() c, d, e

fun3() d, e, f

fun1() b, c, d,

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun2().

In fun2(), the local variables "c, d, e" of fun2() will be visible

variable "f" of fun3() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

8 0

1 year ago

In this programming assignment, you will create a hierarchy of classes (see below) that inherit from the beverage class. The bas

harina [27]

Answer:

public class GetInfo{

Beverage[] beverages=new Beverage[100];

int i=0;

GetInfo(Beverage b){

beverages[i]=b;

i++;

}

public void Display(){

for(int i=0;i<beverages.length;i++)

cout<<beverage[i].tostring();

}

Explanation:

we are taking Beverages array to store all values and in constructor we are adding that to the list and Display() function prints the vale

5 0

2 years ago

Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer

NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

6 0

2 years ago